Kepler's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. An ellipse can easily be constructed using a pencil, two tacks, a string, a sheet of paper and a piece of cardboard. Tack the sheet of paper to the cardboard using the two tacks. Then tie the string into a loop and wrap the loop around the two tacks. Take your pencil and pull the string until the pencil and two tacks make a triangle (see diagram at the right). Then begin to trace out a path with the pencil, keeping the string wrapped tightly around the tacks. The resulting shape will be an ellipse. An ellipse is a special curve in which the sum of the distances from every point on the curve to two other points is a constant. The two other points (represented here by the tack locations) are known as the foci of the ellipse. The closer together that these points are, the more closely that the ellipse resembles the shape of a circle. In fact, a circle is the special case of an ellipse in which the two foci are at the same location. Kepler's first law is rather simple - all planets orbit the sun in a path that resembles an ellipse, with the sun being located at one of the foci of that ellipse.
Answer:
Explanation:
position
y(t) = 2.80t + 0.61t³
velocity is the derivative of position
v(t) = 2.80 + 1.83t²
acceleration is the derivative of velocity
a(t) = 3.66t
F = ma = 5.50(3.66(4.10)) = 82.533 N
which should be rounded to no more than three significant digits and arguably only two due to the 0.61 factor.
F = 82.5 N or 83 N
Yes the units are Newtons, cannot tell what your system will accept. May not want the units at all.
Answer : The cell emf for this cell is 0.077 V
Solution :
The balanced cell reaction will be,
Oxidation half reaction (anode): 
Reduction half reaction (cathode): 
In this case, the cathode and anode both are same. So, 
is equal to zero.
Now we have to calculate the cell emf.
Using Nernest equation :
![E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}{diluted}}{[Zn^{2+}{concentrated}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7D%5Clog%20%5Cfrac%7B%5BZn%5E%7B2%2B%7D%7Bdiluted%7D%7D%7B%5BZn%5E%7B2%2B%7D%7Bconcentrated%7D%5D%7D)
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
![[Zn^{2+}{diluted}]](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%7Bdiluted%7D%5D)
= 0.0111 M
![[Zn^{2+}{concentrated}]](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%7Bconcentrated%7D%5D)
= 4.50 M
Now put all the given values in the above equation, we get:
Therefore, the cell emf for this cell is 0.077 V
Answer:
Explanation:
The time period of the pendulum containing simple pendulum is given by
where, L is the length of the pendulum and g is the value of acceleration due to gravity.
The time period of the clock using the spring mechanism is given by
where, m is the mass of the block attached to the spring and k is the spring constant.
here we observe the time period of the pendulum depends on the value of acceleration due to gravity. The value of acceleration due to gravity decreases as we go on the heights that means when the clock is taken to the mountain, the value of g decreases and thus, the value of time period increases and the clock runs slow.
So, the clock containing the spring system gives the accurate reading rather than the clock containing simple pendulum.
