we know that Bob can do the whole job in 14 hours, how much of the work has he done in 1 hour only? well since he can do the whole lot in 14 hours in 1 hour he has only done 1/14 th of the job.
we know that James can do it in 18 hours, a bit slower, so in 1 hour he has done only 1/18 th of the job.
let's say it takes both of them working together say "t" hours, so in 1 hour Bob has done (1/14) of the work whilst James has done (1/18) of the work, the whole work being t/t or 1 whole, so for just one hour that'd 1/t done by both Bob and James.

Answer:
I think the answer is B. I could be wrong tho, love.
Y = 2x/x-7
x = 2y/y-7
xy - 7x = 2y
-7x = 2y - xy
-7x = y(2-x)
y = -7x / 2-x
y = 7x / x-2
f-¹(x) = 7x / x-2
Answer:
21 packages
Step-by-step explanation:
4 ÷3/16= 4 x 16= 64/3=21 1/3 . 21 packages
hope this helps :)
Answer:
(x - 2) • (4x + 1)
Step-by-step explanation: