Answer: the speed of the plane in still air is 135 km/h
the speed of the wind is 23 km/h
Step-by-step explanation:
Let x represent the speed of the plane in still air.
Let y represent the speed of the wind.
Flying to England with a tailwind a plane averaged 158km/h. This means that the total speed of the plane is (x + y) km/h. Therefore,
x + y = 158 - - - - - - - - - - - - - -1
On the return trip, the plane only averaged 112 km/h while flying back in the same wind. This means that the total speed of the plane is (x - y) km/h. Therefore,
x - y = 112 - - - - - - - - - - - - - -2
Adding equation 1 to equation 2, it becomes
2x = 270
x = 270/2 = 135 km/h
Substituting x = 135 into equation 2, it becomes
135 - y = 112
y = 135 - 112
y = 23 km/h
if two mind readers read each others mind... who's mind are they reading?
The first thing you should know are properties of exponents to solve the problem.
For this case the radical form is given by the writing of the expression in the form of root.
We have then:
t^-3/4 =4^root(t^-3)=4^root ((1)/(t^3))
answer t^-3/4=4^root((1)/(t^3))
Answer:
answer is D
Step-by-step explanation:
because to even it out, you would need ore ones to have rolled to make an average
First we need to find where the 2 graphs intercept.
x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0
2x(x - 2)
x = 0 , 2. are x coordinates of the 2 intercepts.
