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2 years ago

7

It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 g

allon =3.7L; the density of water is 1.0g/ml ) Show your work

2 answers:

dimulka [17.4K]2 years ago

7 0

Answer:

0.1g (Gallon) of chlorine

Explanation:

<u>Formula</u>

1 gallon = 3.7L; the density of water is 1.0g/ml

<u>Given</u>

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

<u>Solve</u>

If 2g (gallon) chlorine = 1,000,000g (gallon)

∴, ? chlorine = 40,000

The First step; set up an equation

1000000/2 = 40000/?

The Next step; divide 1 million to 2

1000000 ÷ 2 = 500000

Then, divide the result by 40000

40000 ÷ 500000 = 0.08

In the nearest unit that is 0.1

Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

riadik2000 [5.3K]2 years ago

6 0

Answer:

296

Explanation:

1 gallon = 3.7 L

40,000 gallon

= 40,000 × 3.7

= 148,000 L

1 g = 1 / 1000 L

1,000,000 g

= 1,000,000 / 1000

= 1,000 L

Let x be the amount of chlorine that will it take to sanitize a 40,000-gallon pool.

2 : 1,000 : : x : 148,000

2 / 1,000 = x / 148,000

x × 1,000 = 2 × 148,000

x = ( 2 × 148,000 ) / 1,000

= 2 × 148

x = 296 g

Therefore,

296 g of chlorine will it take to sanitize a 40,000-gallon pool.

( I solved using maths )

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