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shtirl [24]
3 years ago
13

How many liters of air must react with 2500 mL of hexane in order for combustion to occur completely. The percentage of oxygen i

n air is 20.9%.
Chemistry
1 answer:
bagirrra123 [75]3 years ago
7 0

Answer:

118750 ml

Explanation:

The chemical equation for complete combustion of hexane is given as;

2C6H14 + 19O2 → 12CO2 + 14H2O  

From the equation of the reaction;

2 mol of C6H14 reacts with 19 mol of O2

2 ml of C6H14 reacts with 19 ml of O2

2500 mL of C6H14 would react with x ml of O2

2 = 19

2500 = x

x = 2500 * 19 / 2 = 23750 ml

Since oxygen is 20% of air;

23750 = 20 / 100 * (Volume of air)

Volume of air = 23750 * 100 / 20 = 118750 ml

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Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

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