Answer:
0.374 Pound Approximately
Solution:
Gram and Pound are related as,
1 Gram = 0.0022 Pound (approximately)
As we are given with 170 g of French Fries, so it can be converted into pounds as,
1 Gram = 0.0022 Pound
So,
170 Grams = X Pounds
Solving for X,
X = (170 Gram × 0.0022 Pounds) ÷ 1 Gram
X = 0.374 Pound Approximately
Answer:
a) S = 0.0152 mol/L
b) S' = 4.734 g/L
Explanation:
S 2S S...............in the equilibrium
- Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]
a) molar solubility:
⇒ Ksp = ( 2S) ² * S = 1.4 E-5
⇒ 4S² * S = 1.4 E-5
⇒ S = ∛ ( 1.4 E-5 / 4 )
⇒ S = 0.0152 mol/L
b) solubility ( S' ) in grams per liter:
∴ Mw Ag2SO4 = 311.799 g/mol
⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )
⇒ S' = 4.734 g/L
The answer is speed
Distance/time=speed