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3 years ago

A solution has a hydrogen ion concentration of 6.8 10–3 M. (2 points) i. What is the pH of the solution? Show your work.

Chemistry

1 answer:

vladimir2022 [97]3 years ago

8 0

Answer:

2.17

Explanation:

To calculate pH using the hygrogen ion concentration we must use the following formula:

- log (H+) = pH

All we have to do now is plug in our hygrogen ion concentration and put it in our calculator.

- log (6.8 × 10⁻³) = 2.17

Don't forget proper figures for pH!

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Calculate for the following electrochemical cell at 25°C, Pt H2(g) (1.0 atm) H (0.010 M || Ag (0.020 M) Ag if E (H) - +0.000 V a

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Answer : The correct option is, (b) +0.799 V

Solution :

The values of standard reduction electrode potential of the cell are:

$E^0_{[H^{+}/H_2]}=+0.00V$

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From the cell representation we conclude that, the hydrogen (H) undergoes oxidation by loss of electrons and thus act as anode. Silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : $H_2\rightarrow 2H^{+}+2e^-$

Reaction at cathode (reduction) : $Ag^{+}+1e^-\rightarrow Ag$

The balanced cell reaction will be,

$H_2+2Ag^{+}\rightarrow 2H^{+}+2Ag$

Now we have to calculate the standard electrode potential of the cell.

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{[Ag^{+}/Ag]}-E^o_{[H^{+}/H_2]}$

$E^o_{cell}=(+0.799V)-(+0.00V)=+0.799V$

Therefore, the standard cell potential will be +0.799 V

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3 years ago

What mass of mgo is produced from 2.00 moles of mg ? Mg +02 mgo

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2 years ago

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