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enot [183]
2 years ago
6

Question 6 of 10

Chemistry
2 answers:
RSB [31]2 years ago
7 0

Answer:

A

Explanation:

Elenna [48]2 years ago
3 0

Answer:

A via A P E X

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How many moles of H2 will be produced from 100 moles of water?2 H2O → 2 H2 + O2
ki77a [65]

In order to answer this question, we are going to look at the molar ratio between H2O and H2, we can see that by analyzing the numbers in front of the compounds, and we can see that the molar ratio is 2:2, this means that for every 2 moles of water decomposing, we will end up with 2 moles of H2 being produced, therefore the same amount of moles for H2O will be the same amount of moles of H2, which means that if we have 100 moles of H2O being decomposed, we will also have 100 moles of H2 being produced.

7 0
1 year ago
ethanol and benzene dissolve in each other. when ml of ethanol is dissolved in l of benzene, what is the mass of the mixture?
dsp73

The total mass of the mixture will be "958.5 g".

Calculation ,

According to the question, the density of both the mixtures will be:

Ethanol = 0.785 g/mL ( given )

Benzene = 0.880 g/mL ( given )

The volume of both the mixtures,

Ethanol = 100 mL ( given )

Benzene = 1.00 L or 1000 mL  ( given )

As we know,

density = mass/volume

now,

The mass of Ethanol will be:

mass = density × volume =  0.785 g/mL × 100 mL

mass  = 78.5 g

The mass of Benzene will be:

mass = density × volume =   0.880 g/mL  × 1000 mL

mass  = 880 g

hence,

The total mass of the mixture = 78.5 g + 880 g = 958.5 g

Missing data ,

density of Ethanol = 0.785 g/mL

density of Benzene = 0.880 g/mL

The volume of both the mixtures,

Ethanol = 100 mL

Benzene = 1.00 L

Learn more about mass of the mixture here:

brainly.com/question/15189339

#SPJ4

8 0
1 year ago
7.24 miles of Ag(PO4)2
Vladimir [108]
7.42 moles of Ag(PO4)2 x 297.8109g / 1 moles = 2210g Ag(PO4)2
7 0
3 years ago
A mixture of C3H8C3H8 and C2H2C2H2 has a mass of 2.8 gg . It is burned in excess O2O2 to form a mixture of water and carbon diox
julsineya [31]

Answer:

gghhgyuhuyyugffygcggyy

8 0
3 years ago
A gas has a volume of 5.0 L at a pressure of 50 KPa. What happens to the volume when the pressure is increased to 125?
Alexeev081 [22]
The volume becomes two. You have to use the equation P1 x V1 = P2 x V2 
P is pressure and V is volume.
P1 = 50     P2 = 125
V1 = 5       V2 = v (we don't know what it is)
Then set up the equation:
50 times 5 = 125 times v
250 = 125v
the divide both sides by 125 and isolate v
2 = v
Therefore the volume is decreased to 2.
Also, Boyle's Law explains this too: Volume and pressure are inversely related, This means that when one goes up the other goes down (ie when pressure increases volume decreases and vice versa). Becuase the pressure went up from 50 KPa tp 125 KPa the volume had to decrease.

7 0
3 years ago
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