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Marat540 [252]
3 years ago
13

a graduated cylinder has 35.0 mL of water in it before an object is dropped inside. the new volume is 38.5 mL. What is the volum

e of the objext in cm3
Chemistry
1 answer:
tino4ka555 [31]3 years ago
4 0
Displaced volume:

final volume - initial volume

1 mL = 1 cm³

38.5 mL - 35.0 mL = 3.5 cm³

hope this helps!
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Which is an element?<br> A: H20<br> B: NaCl<br> C: Mg<br> D: CO
Talja [164]
The answer is option D "CO." Co also known as Cobalt is the 27th element on the periotic table. It was discovered in <span>1735, it's boiling point is 3200 k.</span>

Atomic mass: 58.9332
Protons: 27
Neutrons: 32
Electrons: 27

Hope this helps!

3 0
3 years ago
Read 2 more answers
For a lake in Michigan, researchers have determined that largemouth bass feed on smaller fish, which in turn feed on zooplankton
allsm [11]

Answer:

the expected decline in largemouth bass is 3,000 kg.

Option d) 3,000 kg is the correct answer.

Explanation:

Given the data in the question;

In 2016, there was 600,000 kg of zooplankton in the lake.

In 2017, an accidental runoff of insecticide near the lake caused a 50 percent decline of the zooplankton population in the lake.

Now,

The remaining mass of zooplankton  after the 50% decline will be;

⇒ 600,000 kg zooplankton  × 50%

⇒ 600,000 × 50/100

⇒ 300,000 kg of zooplankton

Now, with 10 percent trophic efficiency;  smaller fish directly feed on zooplankton; decline in smaller fish mass will be;

⇒ 300,000 kg × 10%

⇒ 300,000 × 10/100

⇒  30000 kg

Finally, with 10 percent trophic efficiency, largemouth bash directly feed on smaller fish, so the expected decline in mass of largemouth bash will be;

⇒ 30000 kg × 10%

⇒ 30000 kg × 10/100

⇒ 3,000 kg

Therefore, the expected decline in largemouth bass is 3,000 kg.

Option d) 3,000 kg is the correct answer.

7 0
3 years ago
NEED HELP WITH THIS CHEMISTRY QUESTION
denis-greek [22]

Answer:

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Explanation:

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8 0
3 years ago
Felix adds salt to the boiling water, what will he have in the pot?
Pani-rosa [81]
A mixture called a solution, I think.
8 0
3 years ago
1. What pressure would be exerted by 46.0grams of hydrogen gas placed into a 3.00 L container at
dlinn [17]

Answer:

187.34 atm

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

make P the subject of the equation

P = nRT/V.............. Equation 2

n = mass(m)/molar mass(m')

n = m/m'............... Equation 3

Substitute equation 3 into equation 2

P = (m/m')RT/V............ Equation 4

Given: m = 46 g, T = 25°C = (25+273) = 298 K, V = 3.00 L

Constant: m' = 2 g/mol, R = 0.082 atmL/K.mol

Substitute these values into equation 4

P = (46/2)(0.082×298)/3

P = (23×0.082×298)/3

P = 187.34 atm

3 0
3 years ago
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