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2 years ago

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a graduated cylinder has 35.0 mL of water in it before an object is dropped inside. the new volume is 38.5 mL. What is the volum

e of the objext in cm3

1 answer:

tino4ka555 [31]2 years ago

4 0

Displaced volume:

final volume - initial volume

1 mL = 1 cm³

38.5 mL - 35.0 mL = 3.5 cm³

hope this helps!

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7. NH2CO2NH4(s) when heated to 450 K undergoes the following reaction to produce a system which reaches equilibrium: NH2CO2NH4(s

Taya2010 [7]

Answer:

Value of equilibrium constant is 0.0888

Explanation:

Both $NH_{3}$ and $CO_{2}$ are gaseous. Hence equilibrium constant depends upon partial pressures of $NH_{3}$ and $CO_{2}$ .

Initially no $NH_{3}$ and $CO_{2}$ were present.

Hence mole fraction of $NH_{3}$ and $CO_{2}$ at equilibrium can be calculated from coefficient of $NH_{3}$ and $CO_{2}$ in balanced equation.

Mole fraction of $NH_{3}$ = (number of moles of $NH_{3}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{2moles}{(2+1)moles}=\frac{2}{3}$

Mole fraction of $CO_{2}$ = (number of moles of $CO_{2}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{1moles}{(2+1)moles}=\frac{1}{3}$

Let's assume both $CO_{2}$ and $NH_{3}$ behaves ideally.

Therefore partial pressure of $NH_{3}$ , $P_{NH_{3}}= x_{NH_{3}}.P_{total}$ and P_{CO_{2}}= x_{CO_{2}}.P_{total}

Where x represents mole fraction

So, $P_{NH_{3}}=\frac{2}{3}\times 0.843atm=0.562atm$

$P_{CO_{2}}=\frac{1}{3}\times 0.843atm=0.281atm$

So, $K_{p}=P_{NH_{3}}^{2}.P_{CO_{2}}=(0.562)^{2}\times 0.281=0.0888$

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2 years ago

PLEASE HURRY Which element has the largest atomic radius?<br><br> As<br> N<br> P<br> Sb

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3 years ago

Read 2 more answers

Cuántos mililitros de agua hay en 3 litros de una botella de naranjas y las solucion tiene una concentracion de 20% v/v

sertanlavr [38]

Respuesta:

2400 mL

Explicación:

Paso 1: Información dada

Volumen de solución: 3 L (3000 mL)

Concentración de naranja: 20 % v/v

Paso 2: Calcular el volumen de naranja

La concentración de naranja es de 20 % v/v, es decir, cada 100 mL de solución hay 20 mL de naranja.

3000 mL Sol × 20 mL Naranja/100 mL Solución = 600 mL Naranja

Paso 3: Calcular el volumn de agua

El volumen de soluciónes igual a la suma de los volúmenes de naranja y agua.

VSolución = VNaranja + VAgua

VAgua = VSolución - VNaranja

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2 years ago

Calculate the molality of a 5.73 M ethanol (C2H5OH) solution whose density is 0.9327 g/mL.

Natalka [10]

Answer:

Molality = 8.57 m

Explanation:

Given data:

Molarity of solution = 5.73 M

density = 0.9327 g/mL

Molality of solution = ?

Solution:

Molality = moles of solute / kg of solvent.

Kg of solvent:

Mass of 1 L solution = density× volume

Mass of 1 L solution = 0.9327 g/mL × 1000 mL

Mass of 1 L solution = 932.7 g

Mass of solute:

Mass of 1 L = number of moles × molar mass

Mass = 5.73 mol × 46.068 g/mol

Mass = 263.97 g

Mass of solvent:

Mass of solvent = mass of solution - mass of solute

Mass of solvent = 932.7 g - 263.97 g

Mass of solvent = 668.73 g

In Kg = 668.73 /1000 = 0.6687 Kg

Molality:

Molality = number of moles of solute / mass of solvent in Kg

Molality = 5.73 mol / 0.6687 Kg

Molality = 8.57 m

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2 years ago

How to calculate percentage change in mass

blondinia [14]

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This calculation shows what proportion of the initial </span>mass<span> changed. To find the </span>percent change<span>, simply multiply this number by 100</span>

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3 years ago