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nydimaria [60]
3 years ago
12

The concentration of carbon monoxide in an urban apartment is 48 μg/m3. What mass of carbon monoxide in grams is present in a r

oom measuring 10.0 × 10.5 × 22.5 ft?
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer:

The answer is 3213.6 grams.

Explanation:

In meters the room dimensions are 3.05-3.2-6.86.

Total volume of the room is:

3.05*3.2*6.86=66.95

66.95 m3.

The density of carbon monoxide is 48 g/m3. Then total grams is present in a room measuring:

66.95*48=3213.6

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8. A 3.0 x 10' g nerf projectile is fired from a 1.5 kg nerf gun. If the velocity of the projectile is
tatuchka [14]

Answer:

v_g=0.2\ m.s^{-1}

Explanation:

Given:

  • mass of nerf projectile, m_p=30\ g=0.03\ kg
  • velocity of nerf projectile, v_p=10\ m.s^{-1}
  • mass of the gun, m_g=1.5\ kg

Now in this case the collision can be assumed to be perfectly elastic.

<u>For an elastic collision:</u>

m_p.v_p=m_g.v_g

where:

v_g= recoil velocity of the gun

0.03\times 10=1.5\times v_g

v_g=0.2\ m.s^{-1}

4 0
2 years ago
Astronomers have divided the planets into two groups. The inner, “terrestrial,” planets are Mercury, Venus, Earth, and Mars. The
algol [13]

Answer:

it's letter C because inner planets are warmer because they are close to the sun and they are smaller than the Jovian or Giant Gas Planets which have rings, and cooler.

3 0
2 years ago
Identify the role of organisms in this food chain.
Llana [10]

Answer:

the grass is the producer, the mushroom is the decomposer, the dragonfly is the primary consumer, the frog is the secondary, and the hawk is the tertiary consumer.

Explanation:

Hope this helps :)

8 0
3 years ago
Read 2 more answers
Im a freshman in highschool pls help
Vsevolod [243]
Well I can help you with some... 
1. The answer is 2 Hydrogen and 2 Oxygen
3. 4 Hydrogen and 2 Oxygen
4. 16 Hydrogen and 16 Oxygen
6. 2 H2O
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7 0
3 years ago
Particles q1 = +8.0 °C, 92 = +3.5 uc, and
WINSTONCH [101]

Answer:

Explanation:

q₁ = 8 x 10⁻⁶ C , q₂ = 3.5 x 10⁻⁶ C , q₃ = -2.5  x 10⁻⁶ C

Force between charge = 9 x 10⁹ x q₁ q₂ / d²

Force on q₁ due to q₂

= 9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶  /( .10 )²

= 25.2 N . This force will be negative as it will point towards left ( q₂ will repel q₁ )

Force on q₁ due to q₃

= 9 x 10⁹ x 8 x 10⁻⁶ x 2.5 x 10⁻⁶  /( .15 )²

= 8 N . This force will be negative as it will point towards left ( q₃ will attract  q₁ )

Net force = 25.2 N - 8 N

= 17.2 N .

8 0
2 years ago
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