Answer:
0.038 m/s, 0.0096 m/s²
0.101
0.103
Explanation:
The speed is given by
v = 2πr / T
v = (2 * π * 0.15) / 25
v = 0.9426 / 25
v = 0.038 m/s
Acceleration, a is given by
a = v² / r =
a = 0.038² / 0.15
a = 0.001444 / 0.15
a = 0.0096 m/s²
Ratio of apparent weight to true weight at the top
w = m (g - a) / (m g)
w = 1 - a/g
w = 1 - 0.0096 / 9.81
w = 0.9904 / 9.81
w = 0.101
Ratio of apparent weight to true weight at bottom
w = m (g+a)/ (m g)
w = 1 + a/g
w = 1 + 0.0096 / 9.81
w = 1.0096 / 9.81
w = 0.103
Answer:
5m/s²
Explanation:
The force exerted on an object is calculated using the formula ;
F = ma
Note that the upward force (F) is 148N
Where;
F = force (N)
m = mass (kg)
a = acceleration (m/s²)
The downward force towards gravity is F' = mg
F' = 10 × 9.8m/s²
F' = 98N
Net force (F - F') = m × a
148 - 98 = 10 × a
50 = 10a
a = 50/10
a = 5m/s²
Answer: A) length of string.
