Answer:
3
Step-by-step explanation:
Answer:
and 
Step-by-step explanation:
The equation of curve is

We need to find the equation of the tangent line to the curve at the point (-3, 1).
Differentiate with respect to x.
![2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})](https://tex.z-dn.net/?f=2%5B2%28x%5E2%2By%5E2%29%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E2%2By%5E2%29%5D%3D25%282x-2y%5Cfrac%7Bdy%7D%7Bdx%7D%29)

The point of tangency is (-3,1). It means the slope of tangent is
.
Substitute x=-3 and y=1 in the above equation.





Divide both sides by 130.

If a line passes through a points
with slope m, then the point slope form of the line is

The slope of tangent line is
and it passes through the point (-3,1). So, the equation of tangent is


Add 1 on both sides.


Therefore,
and
.
Answer:
(Q + R)(P - Q)
Step-by-step explanation:
PQ + PR - RQ - Q² = (Q + R)(P - Q)
Linear means the highest exponent on the placholder is 1
it is also just a straight line
y=|x| is like y=(√x)², it is 2 straight lines
B. y=x², exponent is 2 so no
C. y=-3x³, exponent is 3, so no
D. y=1/4x, yep
D is the answer
I think that the answer would be 2 if I am right