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svetlana [45]
3 years ago
13

What is 2.3 x 10^3?

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0

2300 is ur answer.............

anastassius [24]3 years ago
5 0

2300 your welcome best friends

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6. In right triangle ABC, mZC=3y-10,
lorasvet [3.4K]

Answer:

scalene

Step-by-step explanation:

step 1

Find the value of y

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

In this problem

m∠A+m∠B+m∠C=180°

substitute the given values

90\°+(y+40)\°+(3y-10)\°=180\°

Solve for y

4y+120=180

4y=180-120

4y=60

y=15

step 2

<em>Find the measure of angle B</em>

m∠B=(y+40)°

substitute the value of y

m∠B=(15+40)=55°

step 3

<em>Find the measure of angle C</em>

m∠C=(3y-10)°

substitute the value of y

m∠C=(3(15)-10)=35°

The three interior angles are different

so

The three sides of the ABC triangle will also be different

therefore

The right triangle ABC is scalene

6 0
3 years ago
Equations that equal 12
crimeas [40]
I hope this helps you


12=3.4=3.2^2
6 0
3 years ago
Read 2 more answers
Simplify X 1/2 times X 2/3
vovikov84 [41]

Answer:

3/6x • 4/6x

12/6x

2x

Step-by-step explanation:

you would change both fractions to have the same denominator then simplify if needed

5 0
3 years ago
Solve the following quadratic equation 6x2 – 7x = 20
siniylev [52]

Answer:

<h2>x = 5/2 , x = - 4/3</h2>

Step-by-step explanation:

6x² - 7x - 20 = 0

Using method of factorization

Rewrite - 7x as a difference

That's

6x² + 8x - 15x - 20 = 0

Factor the expression

That's

2x( 3x + 4) - 5( 3x + 4) = 0

Which is

(2x - 5) (3x + 4) = 0

2x - 5 = 0

2x = 5

Divide both sides by 2

x = 5/2

3x + 4 = 0

3x = - 4

Divide both sides by 3

x = -4/3

Hope this helps you

5 0
3 years ago
Read 2 more answers
Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((
Alexus [3.1K]

Answer:

q^{-30}

Step-by-step explanation:

Given the expression:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}

First, we open the outer brackets

=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}

Therefore:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30

8 0
4 years ago
Read 2 more answers
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