65.99(0.15)
Now take that number and subtract it from the original cost
65.99-9.9
56.09
What is the algebraic expression?
Step-by-step explanation:
Left-hand-side:
\displaystyle \dfrac{1}{sec(x) - tan(x)}
sec(x)−tan(x)
1
\displaystyle = \ \dfrac{1}{sec(x) - tan(x)} * \dfrac{sec(x) + tan(x)}{sec(x) + tan(x)}=
sec(x)−tan(x)
1
∗
sec(x)+tan(x)
sec(x)+tan(x)
\displaystyle = \ \dfrac{sec(x) + tan(x)}{sec^2(x) - tan^2(x)}=
sec
2
(x)−tan
2
(x)
sec(x)+tan(x)
Now use
\displaystyle 1 + tan^2(x) \ = \ sec^2(x)1+tan
2
(x) = sec
2
(x)
and you should be done.....
Answer:
Step-by-step explanation:
Given,
Time taken (t) = 10 - 6 = 4hrs
Water decreased (V) = 24000l - 18000l = 6000l
Now,
average rate of decrase (Avg) = V/t = 6000l/4 =1500 L/h
1A=12 oz
1B=16×2=32 6×2=12
32÷16=2
Since 32÷16=2 then you have to multiply 6 and 2 to get your answer which is 12oz<span />
