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umka21 [38]
3 years ago
7

A useful application of oxalic acid is the removal of rust (fe2o3) from, say, bathtub rings according to the reaction below. fe2

o3(s) + 6 h2c2o4(aq) 2 fe(c2o4)33−(aq) + 3 h2o + 6 h+(aq) calculate the number of grams of rust that can be removed by 8.00 ✕ 102 ml of a 0.800 m solution of oxalic acid.
Chemistry
1 answer:
Butoxors [25]3 years ago
3 0

Answer: 170.9 g


Explanation:



1) Balanced chemical equation:


Fe₂O₃(s) + 6 H₂C₂O₄ (aq) → 2Fe(C₂O₄)₃³⁻ + 3H₂O + 6H⁺(aq)


2) mole ratio:


1mol Fe₂O₃ : 6 mol H₂C₂O₄


3) number of moles of H₂C₂O₄ in the solution


M = n / V ⇒ n = MV = 0.800M × 0.800 liter = 6.40 moles


4) Porportionality


1mol Fe₂O₃ / 6 mol H₂C₂O₄ = x / 6.40 mol H₂C₂O₄


⇒ x = 1.07 mol Fe₂O₃


5) Convert 1.07 mol Fe₂O₃ to grams.


molar mass Fe₂O₃ = 159.69 g/mol


mass in grams = molaer mass × number of moles


mass in grams = 159.69 g/mol × 1.07 mol = 170.9 g

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