KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol
HNO3= 1 mol KOH (keep in mind this because it will be used later).
We also know that 0.100 M KOH aqueous
solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the
definition of molarity).
First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/
1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.
Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.
The final answer is </span>(2) 20.0 mL.<span>
Also, this problem can also be done by using
dimensional analysis.
Hope this would help~
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The answer is A) each side of the equations is divided by the number of moles.
The combined gas law equation
P1V1/T1 = P2V2/T2
becomes
P1V1/n1T1 = P2V2/n2T2
with the addition of Avogadro's law relating volume and number of moles of a gas.This modification is when the number of moles of gas in a sample is allowed to change in addition to pressure, temperature and volume. This also means that pressure multiplied by the volume and divided by the product of the number of moles and temperature is a constant:
PV/nT = constant
which if written in the form PV = nRT is the ideal gas law equation where R is the gas constant.
Answer:
1000 gram
Explanation:
because mass is constant everywhere
Answer: the new pressure will be 300mmHg
Explanation:
V1 = 30L.
V2 = 50L
P1 = 500mmHg
P2 =?
P1V1 = P2V2
30 x 500 = P2 x 50
P2 = (30 x 500) / 50
P2 = 300mmHg
Answer:
2 mol of CO₂
Solution:
The reaction is as follow,
H₂CO + O₂ → CO₂ + H₂O
According to this equation,
1 mole of H₂CO produces = 1 mole of CO₂
So,
2 moles of H₂CO will produce = X moles of CO₂
Solving for X,
X = (2 mol × 1 mol) ÷ 1 mol
X = 2 mol of CO₂