Answer:
=5 protons, 6 neutrons,5 electrons
All atoms of boron always contain 5 protons, as that defines its atomic number 5, Boron atomic number 5 has five electrons in its ground state.
Commonly Boron will lose 3 electrons leaving 2 electrons in its most common ionic form,all atoms of boron always contain 5 protons, as that defines its atomic number 5
The mass number for boron-11 is 11 (it's given to you), and recall that the number of protons plus the number of neutrons equals the mass number.
A 11B atom thus contains 11(mass number)−5(protons)=6 neutrons
The atomic number gives the number of protons,protons which have a positive charge are balanced by an equal number of electrons in a neutral atom.
Boron number 5 has five protons and therefore as a neutral atom also has five electrons.
Boron has an electron configuration of 1s22s22p1
The most stable electron configuration for Boron is 1s2 + 3 charge,by losing three electrons Boron can achieve the stable electron structure of Helium
Explanation:
Well the answer is 207.2. You take the lowest sig figs that you are using which would be 2500= 2 sig figs. 207.2 rounded to 2 sig figs would be 210
Answer:
Metallic character refers to the level of reactivity of a metal. Non-metallic character relates to the tendency to accept electrons during chemical reactions. Metallic tendency increases going down a group. Non-metallic tendency increases going from left to right across the periodic table.
Explanation:
I hope this helps :)
I think c is the right answer