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2 years ago

Footlocker sold 72 pairs of the new Adidas tennis shoes for $69. How much did the store make for selling the tennis shoes?

Mathematics

2 answers:

Slav-nsk [51]2 years ago

7 0

Answer: $4,968

Step-by-step explanation:

Rama09 [41]2 years ago

5 0

4,968 dollars you just have to multiply 72 x 69

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Use the balanced scale to find the conversion factor that can be used to convert the number of blocks to the weight of the block

77julia77 [94]

Answer:

x = 2 1/4 or 2.25

Step-by-step explanation:

to start we can make an equation

9lbs = 4x

divide by 4

9/4 = x

x = 2.25 or 2 1/4

4 0

2 years ago

Find the greatest common factor

Lerok [7]

Answer:

(3b + 4) is the greatest common factor

Step-by-step explanation:

$3b(2b- 3)+4(2b-3) = 0 \\ {6b}^{2} - 9b + 8b - 12 = 0 \\ {6b}^{2} - b - 12 = 0 \\ {6b}^{2} - 9b + 8b - 12 = 0 \\ 3b(2b - 3) + 4(2b - 3) = 0 \\ (2b - 3)(3b + 4) = 0$

5 0

3 years ago

Jocelyn just accepted a job at a new company where she will make an annual salary of $70000. Jocelyn was told that for each year

Oksanka [162]

Answer:

$80,500

55,500 + 1,500t

Step-by-step explanation:

The question is an arithmetic progression series

Where,

a= first term

d= common difference

n= number of terms

a = $70,000

d= $1,500

n= 8 years

8th term = a + (n-1) d

= 70,000 + (8-1)1500

= 70,000 + 7(1500)

= 70,000 + 10,500

= $80,500

Jocelyn salary after 8 years is $80,500

Solve for when n = t

t th term = a + (n-1)d

= 70,000 + (t - 1)1500

= 70,000 + 1,500t - 1,500

= 55,500 + 1,500t

t th term = 55,500 + 1,500t

4 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$