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kumpel [21]
2 years ago
9

Help Help Find Area Pls!

Mathematics
1 answer:
hodyreva [135]2 years ago
5 0

Answer:

A=600\picm^{2} ; Approx. 1884.95559215 cm^2

Step-by-step explanation:

A=2\pi rh+2\pi r^2\\A=2\pi 10*20+2\pi 10^2\\A=400\pi +200\pi \\A=600\pi

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A furnace operates at 2,300°F.
Cloud [144]

Answer:

T = 2,300 + q × 250

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3 years ago
I need your help please!
Aneli [31]

Answer:

1 mile is mapped to 0.3428 inches i.e. unit rate is 0.3428 inches/mile.

Step-by-step explanation:

Given that the scale of the map is \frac{3}{10} inches = \frac{7}{8} miles ....... (1)

Now, we have to convert this map scale to a unit rate.

And the unit rate is the number of inches per mile.  

As the scale is constant, therefore from the the relation (1) we get  

1 mile = \frac{3 \times 8}{10 \times 7} = 0.3428 inches.

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3 years ago
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Answer:

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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

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3 years ago
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Give me a few and I will
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