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kumpel [21]
3 years ago
9

Help Help Find Area Pls!

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

A=600\picm^{2} ; Approx. 1884.95559215 cm^2

Step-by-step explanation:

A=2\pi rh+2\pi r^2\\A=2\pi 10*20+2\pi 10^2\\A=400\pi +200\pi \\A=600\pi

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Subtract.
LekaFEV [45]

Answer:

7x^(2)-3x+8

Step-by-step explanation:

(5x^(2) - 3x - 2) - (-2x^(2) - +10)

(5x^(2))- (-2x^(2))=7x^(2)

(- 2)-(+10)=+8

7x^(2)-3x+8

6 0
3 years ago
Please help.
iren2701 [21]
A and C are correct.
3 0
4 years ago
Solve the following system of equations please ASAP
swat32

Given:

The system of equation:

x+y = -4 -------- (1)

y = x^{2} -6x --------- (2)

To find the values of x and y.

We will use substitution method.

From (1) we get,

y = -4-x

We will put the value of y in (1) and we get,

-x-4 = x^{2} -6x

or, x^{2} -5x+4= 0

Now we will apply middle term factor method.

  x^{2} -(4+1)x+4 = 0

     x^{2} -4x-x +4 = 0

x(x-4)-1(x-4) = 0

       (x-4)(x-1)= 0

so, x = 4 and 1

Now,

Substitute x = 4 in (1) we get,

y = -4-4 = -8

And putting x = 1 in (1) we get,

y = -4-1 = -5

Hence, the solution of the given system of equation is (4,-8) and (1,-5)

Thus, Option A is the correct answer.

3 0
3 years ago
ASAP WILL MARK BRAINLYEST <br><br><br>answer these two please!
Trava [24]

19.\\y=3x^2\\a=3,\ b=0,\ c=0\\\\\dfrac{-b}{2a}=\dfrac{-0}{2(3)=0\to x=0\\\\3x^2=0\ \ \ \ |:3\\\\x^2=0\to x=0

20.\\y=x^2-x-2\\a=1,\ b=-1,\ c=-2\\\\\dfrac{-b}{2a}=\dfrac{-(-1)}{2(1)}=\dfrac{1}{2}\to x=\dfrac{1}{2}\\\\x^2-x-2=0\\\\x^2-2x+x-2=0\\\\x(x-2)+1(x-2)=0\\\\(x-2)(x+1)=0\iff x-2=0\ \vee\ x+1=0\\\\x=2\ \vee\ x=-1

3 0
3 years ago
Factorize the equation <br>2b2 - 33b + 16 = 0​
Tamiku [17]

Answer:

(2b-1) (b-16)

Step-by-step explanation:

(2b^2-32b)(-b+16)

2b(b-16)  -1(b-16)

3 0
3 years ago
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