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3 years ago

If the radius of a circle is 10cm, what will be the area of the circle?

Mathematics

2 answers:

malfutka [58]3 years ago

5 0

Answer:

314

Step-by-step explanation:

Murljashka [212]3 years ago

4 0

Answer:

Step-by-step explanation:

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PLEASE HELP, THANK YOU! :)

elena-s [515]

Steps to solve:

-4z + 4 + 12z = 3z + 4 + 5z

~Combine like terms

8z + 4 = 8z + 4

~Subtract 4 to both sides

8z = 8z

~Divide 8 to both sides

0 = 0

All real numbers are solutions.

Set builder notation: {x | R}

This is an identity since every value can be a solution to the equation.

Best of Luck!

8 0

3 years ago

If f(n)=(n-1)2+ <img src="https://tex.z-dn.net/?f=f%28n%29%20%3D%20%28n%20-1%292%20%2B%20%20%20%203n" id="TexFormula1" title=

Liono4ka [1.6K]

Distribute the 2 first.

f(n) = 2n - 2 + 3n

Combine like terms.

f(n) = 5n - 2

8 0

3 years ago

Omg please help!!!!! And fast if you can

ruslelena [56]

Answer:

The square root of 10 is 3.16227766017

Step-by-step explanation:

4 0

3 years ago

What is the value of 27÷(−34⋅−45)? 4 16/15 28 4/5 45

MakcuM [25]

Answer:

It would not be any of those answers. it would be 106 :) Its negative numbers divided

5 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

3 years ago