1). c ... 2). d ... 3). a ... 4). d ... 5). c ... 6). a
7). b-mass ... c-m/s ... d-Newton's 1st ... e-Newton's 2nd
Answer:
The radius of orbit=
Explanation:
We are given that
Orbital speed=
m/s
We have to find the radius of orbit of spacecraft.
We know that
Gravitational constant=
Mass of earth=
Orbital speed=
Where G= Gravitational constant
M=Mass of earth
r=Radius of orbit
Substitute the values in the formula
Squaring on both sides
Hence, the radius of orbit=
Answer:
a ) 2.68 m / s
b ) 1.47 m
Explanation:
The jumper will go down with acceleration as long as net force on it becomes zero . Net force of (mg - kx ) will act on it where kx is the restoring force acting in upward direction.
At the time of equilibrium
mg - kx = 0
x = mg / k
= (60 x 9.8 ) / 800
= 0.735 m
At this moment , let its velocity be equal to V
Applying conservation of energy
kinetic energy of jumper + elastic energy of cord = loss of potential energy of the jumper
1/2 m V² + 1/2 k x² = mg x
.5 x 60 x V² + .5 x 800 x .735 x .735 = 60 x 9.8 x .735
30 V² + 216.09 = 432.18
V = 2.68 m / s
b ) At lowest point , kinetic energy is zero and loss of potential energy will be equal to stored elastic energy.
1/2 k x² = mgx
x = 2 m g / k
= (2 x 60 x 9.8) / 800
= 1.47 m
<span>It does not matter where the system starts but it will reach to an equilibrium state when the equilibrium ratio is reached.
hope it helps </span>
B. Decreases
Why: Because the longer the wavelength the lower the frquency. The shorter the wavelength the higher the frequency.
