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3 years ago

If the side of the square below is 10 units, what is the area of the circle?

Mathematics

1 answer:

hram777 [196]3 years ago

7 0

Answer:

area of circle = 78.5 units²

Step-by-step explanation:

diameter = 10 units

radius = 10/2 = 5 units

area = πr² = (3.14)(5²) = 78.5 units²

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Given: QR = 59; RT = 59 Prove: QR = RT StatementsReason 1. QR = 59; RT = 591. Given 2. 59 = RT2. Symmetric Property of Equality

Studentka2010 [4]

Statement 3 is QR=RT. This can be validified by the reason of Transitive Property of Equality. This property is applied when the situation is if a=c and b=c, then a=b. The same is true for QR=59 and RT=59, then QR=RT.

5 0

3 years ago

Read 2 more answers

Find the Area of the figure below, composed of a rectangle and a semicircle.

Mamont248 [21]

Answer:

68.1 units²

Step-by-step explanation:

Start by finding the area of the rectangle...

$Area=lw\\Area=6*9\\Area=54$

Then, find the area of the semicircle...

$Radius=\frac{1}{2}*Diameter=\frac{1}{2}*6=3$

$Area=\frac{1}{2}\pi r^2\\Area=\frac{1}{2}\pi 3^2\\Area=\frac{1}{2}\pi 9\\Area=\frac{9}{2}\ pi\\Area\approx14.1$

Now, add the two to get...

54+14.1=68.1

3 0

2 years ago

Maths functions question

yarga [219]

Answer:

a) OA = 1 unit

b) OB = 3 units

c) AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

$g(x)=2^x$

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

$\implies g(0)=2^0=1$

Therefore, A (0, 1) so OA = 1 unit.

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

$\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}$

Therefore, C (3, 8) so Point B is (3, 0). Therefore, OB = 3 units.

From parts (a) and (b):

A = (0, 1)
B = (3, 0)

To find the length of AB, use the distance between two points formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}$

Therefore:

$\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

$\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}$

$\implies \sf AB=\sqrt{(3)^2+(-1)^2}$

$\implies \sf AB=\sqrt{9+1}$

$\implies \sf AB=\sqrt{10}\:\:units$

5 0

2 years ago

A height of 26 feet and a diameter of 5.6 feet. What is the volume of the geode, rounded to the nearest tenth?

7nadin3 [17]

Answer:

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

Step-by-step explanation:

Given:

Geode shaped approximately like a cylinder. such that

Height = h = 26 feet

Diameter = d = 5.6 feet

$Radius = r =\dfrac{d}{2}=\dfrac{5.6}{2}=2.8\ feet$

To Find:

volume of the geode = ?

Solution:

Geode shaped approximately like a cylinder,

So, Volume of Cylinder is given by,

$\textrm{Volume of Cylinder}=\pi r^{2}h$

Where,

Height = h

Radius = r

pi = 3.14

Substituting the values we get

$\textrm{Volume of Cylinder}=3.14\times 2.8^{2}\times 26=640.05\approx 640.1\ feet^{3}$

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

8 0

3 years ago

Can someone help me plz

natta225 [31]

Answer:

1x3=3

2x3=6

3x3=9

4x3=12

6 0

3 years ago