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Vika [28.1K]
3 years ago
11

If the side of the square below is 10 units, what is the area of the circle?

Mathematics
1 answer:
hram777 [196]3 years ago
7 0

Answer:

area of circle = 78.5 units²

Step-by-step explanation:

diameter = 10 units

radius = 10/2 = 5 units

area = πr² = (3.14)(5²) = 78.5 units²

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Given: QR = 59; RT = 59 Prove: QR = RT StatementsReason 1. QR = 59; RT = 591. Given 2. 59 = RT2. Symmetric Property of Equality
Studentka2010 [4]
Statement 3 is QR=RT. This can be validified by the reason of Transitive Property of Equality. This property is applied when the situation is if a=c and b=c, then a=b. The same is true for QR=59 and RT=59, then QR=RT.
5 0
3 years ago
Read 2 more answers
Find the Area of the figure below, composed of a rectangle and a semicircle.
Mamont248 [21]

Answer:

68.1 units²

Step-by-step explanation:

Start by finding the area of the rectangle...

Area=lw\\Area=6*9\\Area=54

Then, find the area of the semicircle...

Radius=\frac{1}{2}*Diameter=\frac{1}{2}*6=3

Area=\frac{1}{2}\pi r^2\\Area=\frac{1}{2}\pi 3^2\\Area=\frac{1}{2}\pi 9\\Area=\frac{9}{2}\ pi\\Area\approx14.1

Now, add the two to get...

54+14.1=68.1

3 0
2 years ago
Maths functions question
yarga [219]

Answer:

a)  OA = 1 unit

b)  OB = 3 units

c)  AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

g(x)=2^x

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

\implies g(0)=2^0=1

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}

Therefore, C (3, 8) so Point B is (3, 0).  Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

  • A = (0, 1)
  • B = (3, 0)

To find the length of AB, use the distance between two points formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}

Therefore:

\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}

\implies \sf AB=\sqrt{(3)^2+(-1)^2}

\implies \sf AB=\sqrt{9+1}

\implies \sf AB=\sqrt{10}\:\:units

5 0
2 years ago
A height of 26 feet and a diameter of 5.6 feet. What is the volume of the geode, rounded to the nearest tenth?
7nadin3 [17]

Answer:

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

Step-by-step explanation:

Given:

Geode shaped approximately like a cylinder. such that

Height = h = 26 feet

Diameter = d = 5.6 feet

Radius = r =\dfrac{d}{2}=\dfrac{5.6}{2}=2.8\ feet

To Find:

volume of the geode = ?

Solution:

Geode shaped approximately like a cylinder,

So, Volume of Cylinder is given by,

\textrm{Volume of Cylinder}=\pi r^{2}h

Where,

Height = h

Radius = r

pi = 3.14

Substituting the values we get

\textrm{Volume of Cylinder}=3.14\times 2.8^{2}\times 26=640.05\approx 640.1\ feet^{3}

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

8 0
3 years ago
Can someone help me plz
natta225 [31]

Answer:

6

1x3=3

2x3=6

3x3=9

4x3=12

6 0
3 years ago
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