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andre [41]
3 years ago
13

A battleship simultaneously fires two shells toward two identical enemy ships. One shell hits ship A, which is close by, and the

other hits ship B, which is farther away. The two shells are fired at the same speed. Assume that air resistance is negligible and that the magnitude of the acceleration due to gravity is g. What shape is the trajectory (graph of y vs. x) of the shells?a. straight lineb. parabolac. hyperbolad. The shape cannot be determined.
Physics
1 answer:
horsena [70]3 years ago
8 0

Answer:

Parabola.

Explanation:

No matter how far away are the enemy ships, if they are identical or not, or how much is the initial velocity, if the shells are subject to the force of gravity then the shape of their trajectories will follow the same form as with everything else: a parabola.

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Oksana_A [137]

1) Force read on the upper scale: 33.4 N

2) Force read on the lower scale: 43.0 N

Explanation:

1)

The reading on the upper scale is equal to the net force acting on the block of metallic alloy. The net force is given by:

F=W-B (1)

where

W is the weight of the block (downward)

B is the buoyant force (upward)

The weight of the block is given by

W=mg

where m = 3.7 kg is the mass of the block and g=9.8 m/s^2 is the acceleration of gravity.

The buoyant force is given by

B=\rho_w V g

where

\rho_w=1000 kg/m^3 is the water density

V is the volume of the block

The volume of the block can be written as

V=\frac{m}{\rho_b}

where \rho_b=4600 kg/m^3 is the density of the block.

Substituting everything into eq.(1), we find:

F=mg-\rho_w \frac{m}{\rho_b}g=(3.7)(9.8)-(1000)\frac{1.3}{4600}(9.8)=33.4 N

2)

Here we want to find the force on the lower scale.

The force on the lower scale is equal to the difference between the total weight of the system (given by the weight of the beaker + the weight of the water + the weight of the block) and the upper net force exerted on the upper scale, therefore:

F' = m_B g + m_wg+m_b g - F

where:

m_B=1.3 kg is the mass of the beaker

m_w=2.8 kg is the mass of the water

m_b = 3.7 kg is the mass of the block

F=33.4 N is the upper net force

Substituting and solving, we find:

F'=(1.3+2.8+3.7)(9.8)-33.4=43.0 N

Learn more about forces and weight:

brainly.com/question/8459017

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#LearnwithBrainly

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