B. Carbon Dioxide
C. Nitrous Oxide
E. Methane
F. Ozone
Answer:
<em>The answer is B</em>
Explanation:
<em>I got this from study island</em>
Answer:
The final charges of each sphere are: q_A = 3/8 Q
, q_B = 3/8 Q
, q_C = 3/4 Q
Explanation:
This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.
Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point
q_A = Q / 2
q_B = Q / 2
Now sphere A touches sphere C, ending with half the charge
q_A = ½ (Q / 2) = ¼ Q
q_B = ¼ Q
Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge
q = Q / 4 + Q / 2 = ¾ Q
This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q
q_A = 3/8 Q
q_B = 3/8 Q
The final charges of each sphere are:
q_A = 3/8 Q
q_B = 3/8 Q
q_C = 3/4 Q
C.) <span>The total mass of an object can be assumed to be focused at one point, which is called its center of "Mass"
Hope this helps!</span>
Answer:
E = 169.34 J
Explanation:
First, we need to find the frictional force between the back tire and the road. For that purpose, we use the following formula:
f = μR = μW
f = μmg
where,
f = frictional force = ?
μ = coefficient of friction between tire and road = 0.8
g = 9.8 m/s²
m = mass supported by back tire = (0.5)(90 kg) = 45 kg
Therefore,
f = (0.8)(45 kg)(9.8 m/s²)
f = 352.8 N
Now, for the heat energy we use the formula of work. Because, thermal energy will be equal to work done by frictional force:
E = W = fd
where,
E = Thermal Energy = ?
f = frictional force = 352.8 N
d = displacement = 48 cm = 0.48 m
Therefore,
E = (352.8 N)(0.48 m)
<u>E = 169.34 J</u>