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Maurinko [17]
3 years ago
9

Biphenyl, c12h10, is a nonvolatile, nonionizing solute that is soluble in benzene, c6h6. at 25 °c, the vapor pressure of pure be

nzene is 100.84 torr. what is the vapor pressure of a solution made from dissolving 13.6 g of biphenyl in 26.4 g of benzene?
Chemistry
1 answer:
tino4ka555 [31]3 years ago
7 0
One form of Raoult's Law states that the vapor pressure of a solution of a non-volatile solute at certain temperature is equal to the vapor pressure of the pure solvent at the same temperature multiplied by the mole fraction of the solvent, this is:

p = X solvent * P pure solvent,

X solvent = number of moles of solvent / total number of moles.

Here the solute is 13.6 g of C12 H10 and the solvent is 26.4 g C6H6.

=>

moles of solvent = mass in grams / molar mass

molar mass of C6H6 = 6 * 12 g/mol + 6 * 1g/mol = 78 g/mol

moles of solvent = 26.4 g / 78 g/mol = 0.33846 mol

molar mass of C12H10 = 12 * 12g/mol + 10*1g/mol = 154 g/mol

moles of solute = 13.6 g / 154 g/mol = 0.08831 mol

=> X solvent = 0.33846 / (0.33846 + 0.08831) = 0.793

=> p = 0.793 * 100.84 torr = 79.97 torr ≈ 80.0 torr

Answer: 80.0 torr

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Potassium carbonate dissolves as follows:
lara [203]

The 0.25 volume in liters of 1.0 M K_{2}CO_{3} solution is required to provide 0.5 moles of K(aq).

Calculation,

The Potassium carbonate dissolves as follows:

K_{2}CO_{3}(s) → 2K(aq) +CO_{3}^{-2} (aq)

The mole ratio is 1: 2

It means, the 1 mole K_{2}CO_{3} required to form 2 mole of K(aq).

To provide 0.5 mole of K(aq) = 1 mole ×0.5 mole /2 mole required by K_{2}CO_{3}.

To provide 0.5 mole of K(aq) ,0.25 mole required by K_{2}CO_{3}.

The morality of  K_{2}CO_{3} = 1 M = number of moles / volume in lit

The morality of  K_{2}CO_{3} =   1 M = 0.25 mole/ volume in lit

Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit

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5 0
2 years ago
An alcohol is 58.80 % C and 9.889 % H by mass. The rest is oxygen. What is the empirical formula of the alcohol? Enter the eleme
PilotLPTM [1.2K]

Answer:

hco I believe

Explanation:

Pretty sure about this, when do you need to put it in?

6 0
3 years ago
A 76.0-gram piece of metal at 96.0 °C is placed in 120.0 g of water in a calorimeter at 24.5 °C. The final temperature in the ca
anygoal [31]

Answer:

S(metal) = 0.66J/g°C

Explanation:

We can find specific heat of a material, S, using the equation:

q = m*S*ΔT

<em>Where q is change in heat, m is the mass of the substance, S specific heat and ΔT change in temperature.</em>

The heat given by the metal is equal to the heat that water absorbs, that is:

m(Metal)*S(metal)*ΔT(Metal) = m(Water)*S(water)*ΔT(water)

<em>Where:</em>

m(Metal) = 76.0g

S(metal) = ?

ΔT(Metal) = 96.0°C-31.0°C = 65.0°C

m(Water) = 120.0g

S(water) = 4.184J/g°C

ΔT(water) = 31.0°C-24.5°C = 6.5°C

Replacing:

76.0g*S(metal)*65.0°C = 120.0g*4.184J/g°C*6.5°C

S(metal) = 0.66J/g°C

<em />

The law of conservation applies because the energy is not been created or destroyed. The energy that the metal gives is absorbed by the water.

3 0
2 years ago
A solution is 40 cetic acid by mass. the density of this solution is 1.049 g/ml. Calculate the mass of pure acetic acid in 220 m
taurus [48]

The mass of pure acetic acid in 220 ml of the given solution at 20°C is 92.311 g

<h3>What is Acetic acid?</h3>

Acetic acid is a type of carboxylic acid and also known as ethanoic acid

Its formula is CH₃COOH.

It is an organic compound and is a colorless liquid

It is mostly used in the production of vinegar

40 % acetic acid by mass means,

40 g of acetic acid is dissolved in 100 g of solution.

The density of solution at 20°C,

\rho = 1.049 g/ml

We know,

\rho = \frac{m}{V}

V = \frac{m}{\rho}

The volume of the solution, V = \frac{100}{1.049} = 95.33 ml

95.33 ml of solution contains 40 g of pure Acetic acid

220 ml of solution contains\frac{40 \times 220}{95.33} = 92.311 g of pure Acetic acid

Thus, the mass of pure Acetic acid in 220 ml of solution at 20°C is 92.311 g

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7 0
2 years ago
Bromine can be classified as a
sergiy2304 [10]

Answer:

Halogen / salt-former

Explanation:

Bromine is classified as an element in the 'Halogens' section which can be located in group 7 of the Periodic Table. The term "halogen" means "salt-former" and compounds containing halogens are called "salts".

8 0
3 years ago
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