1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maurinko [17]
3 years ago
9

Biphenyl, c12h10, is a nonvolatile, nonionizing solute that is soluble in benzene, c6h6. at 25 °c, the vapor pressure of pure be

nzene is 100.84 torr. what is the vapor pressure of a solution made from dissolving 13.6 g of biphenyl in 26.4 g of benzene?
Chemistry
1 answer:
tino4ka555 [31]3 years ago
7 0
One form of Raoult's Law states that the vapor pressure of a solution of a non-volatile solute at certain temperature is equal to the vapor pressure of the pure solvent at the same temperature multiplied by the mole fraction of the solvent, this is:

p = X solvent * P pure solvent,

X solvent = number of moles of solvent / total number of moles.

Here the solute is 13.6 g of C12 H10 and the solvent is 26.4 g C6H6.

=>

moles of solvent = mass in grams / molar mass

molar mass of C6H6 = 6 * 12 g/mol + 6 * 1g/mol = 78 g/mol

moles of solvent = 26.4 g / 78 g/mol = 0.33846 mol

molar mass of C12H10 = 12 * 12g/mol + 10*1g/mol = 154 g/mol

moles of solute = 13.6 g / 154 g/mol = 0.08831 mol

=> X solvent = 0.33846 / (0.33846 + 0.08831) = 0.793

=> p = 0.793 * 100.84 torr = 79.97 torr ≈ 80.0 torr

Answer: 80.0 torr

You might be interested in
You have 56.8 mL of a gas collected at 664 mmHg and 135 K. What volume will it occupy at 632 mmHg and 196 K? *
tensa zangetsu [6.8K]

Answer:

86.6 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 56.8 mL

Initial pressure (P₁) = 664 mmHg

Initial temperature (T₁) = 135 K

Final pressure (P₂) = 632 mmHg

Final temperature (T₂) = 196 K

Final volume (V₂) =?

The final volume of the gas can be obtained as follow:

P₁V₁/T₁ = P₂V₂/T₂

664 × 56.8 / 135 = 632 × V₂ / 196

Cross multiply

135 × 632 × V₂ = 664 × 56.8 × 196

85320 × V₂ = 7392179.2

Divide both side by 85320

V₂ = 7392179.2 / 85320

V₂ = 86.6 mL

Therefore, the final volume of the gas is 86.6 mL

5 0
3 years ago
Let the simulator run for 30 seconds. What happens to the size of the ice?
Shkiper50 [21]

  1. 10 is your answer hope it helps you.......... Xd
<h2>Answer : 10 </h2>
7 0
3 years ago
How does the density of a Hershey bar compare to the density of the a half bar?How does the density of a Hershey bar compare to
Lostsunrise [7]
IDensity is calculated by mass divided by volume. As you half the Hershey bar, mass and volume change by the same proportion. Therefore, density is the same. 
3 0
3 years ago
The acid dissociation constant, Ka, of HNO3 is 4.0 x104. What does the ka
Shtirlitz [24]

Answer:

i thing its b

Explanation:

3 0
3 years ago
Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w
jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, COCl_2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:  

CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The value of K_c for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which p_{CO}=p_{Cl_2}=0.265atm and p_{COCl_2}=0.000atm ?

<u>Answer:</u> The equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

<u>Explanation:</u>

The relation of K_c\text{ and }K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p = Equilibrium constant in terms of partial pressure

K_c = Equilibrium constant in terms of concentration = 5.79

\Delta n_g = Difference between gaseous moles on product side and reactant side = n_{g,p}-n_{g,r}=1-2=-1

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

T = Temperature = 570 K

Putting values in above equation, we get:

K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

                      CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

<u>Initial:</u>            0.265      0.265

<u>At eqllm:</u>        0.265-x    0.265-x        x

The expression of K_p for above equation follows:

K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}

Putting values in above equation, we get:

0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = (0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of Cl_2=(0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of COCl_2=x=0.008atm

Hence, the equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

6 0
3 years ago
Other questions:
  • ___is the measure of a quantity of energy
    11·2 answers
  • P+Cl &gt; PCl3 <br>Equalize the following chemical equations​
    10·1 answer
  • True or false: if a compound contains ions then both positive and negative ions must be present.
    5·1 answer
  • Mass defect for oxygen-16 = 0.13261 amu How many kilograms does the mass defect represent?1.66 × 10-27 kg
    11·2 answers
  • How many continents is there?
    12·2 answers
  • Write the molecular equation and the net ionic equation for the reaction of solid barium carbonate and hydrogen bromide in aqueo
    5·1 answer
  • A change in the internal energy of a system at constant pressure from a chemical reaction will result in an identical change in
    10·2 answers
  • Which of the following was NOT used in support of the continental drift hypothesis?
    13·1 answer
  • . Find the mass of 2.61 moles of H2O2.
    7·1 answer
  • Which of the units listed below are smaller than a gram? Select all that apply.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!