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Maurinko [17]
3 years ago
9

Biphenyl, c12h10, is a nonvolatile, nonionizing solute that is soluble in benzene, c6h6. at 25 °c, the vapor pressure of pure be

nzene is 100.84 torr. what is the vapor pressure of a solution made from dissolving 13.6 g of biphenyl in 26.4 g of benzene?
Chemistry
1 answer:
tino4ka555 [31]3 years ago
7 0
One form of Raoult's Law states that the vapor pressure of a solution of a non-volatile solute at certain temperature is equal to the vapor pressure of the pure solvent at the same temperature multiplied by the mole fraction of the solvent, this is:

p = X solvent * P pure solvent,

X solvent = number of moles of solvent / total number of moles.

Here the solute is 13.6 g of C12 H10 and the solvent is 26.4 g C6H6.

=>

moles of solvent = mass in grams / molar mass

molar mass of C6H6 = 6 * 12 g/mol + 6 * 1g/mol = 78 g/mol

moles of solvent = 26.4 g / 78 g/mol = 0.33846 mol

molar mass of C12H10 = 12 * 12g/mol + 10*1g/mol = 154 g/mol

moles of solute = 13.6 g / 154 g/mol = 0.08831 mol

=> X solvent = 0.33846 / (0.33846 + 0.08831) = 0.793

=> p = 0.793 * 100.84 torr = 79.97 torr ≈ 80.0 torr

Answer: 80.0 torr

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2) Give the number of lone pairs around the central atom and the molecular geometry of IF5. A) 0 lone pairs, square pyramidal D)
zysi [14]

Answer: D) 1 lone pair, square pyramidal

Explanation:

Formula used  : \text{Number of electrons}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom  = 7

N = number of monovalent atoms bonded to central atom  = 5

C = charge of cation  = 0

A = charge of anion  = 0

Now we have to determine the hybridization of the IF_5  molecule.

\text{Number of electrons}=\frac{1}{2}\times [7+5+0-0]=6

Bond pair electrons = 5

Lone pair electrons = 6-5 = 1

The number of electrons are 6 that means the hybridization will be sp^3d^2 and the electronic geometry of the molecule will be octahedral .

But as there are five atoms around the central iodine atom, the sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square pyramidal.

8 0
2 years ago
Based of the chemical reaction below, if you have 3.56x10^23 molecules of C3H8, how many liters of CO2 gas will be produced at S
LenaWriter [7]

Answer:

39.65L

Explanation:

First, let us calculate the number of mole present in 3.56x10^23 molecules of C3H8.

1 mole of any substance contains 6.02x10^23 molecules as discovered from Avogadro's hypothesis. This means that 1mole of C3H8 contains 6.02x10^23 molecules.

Now, if 1mole of C3H8 contains 6.02x10^23 molecules, then Xmol of C3H8 will contain 3.56x10^23 molecules i.e

Xmol of C3H8 = 3.56x10^23/6.02x10^23 = 0.59mole

The equation for the reaction is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

From the equation above,

1 mole of C3H8 produced 3moles of CO2.

Therefore, 0.59mole of C3H8 will produce = 0.59 x 3 = 1.77mole of CO2.

Now let us calculate the volume occupied by 1.77mole of CO2. This is illustrated below:

1 mole of any gas occupy 22.4L at stp.

Therefore, 1.77mole of CO2 will occupy = 1.77 x 22.4 = 39.65L

Therefore, 39.65L of CO2 are produced.

5 0
3 years ago
Pre-laboratory Questions 1. Using LeChâtelier’s principle, determine whether the reactants or products are favored and the direc
3241004551 [841]
I think the answer is C but don’t quote me on that
8 0
2 years ago
Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

  = 3*2*10^-15 * 10^15

  = 6

Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

                                    = 0.3 -(2*0.089)

                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

4 0
2 years ago
Please help I’m marking a branliest answer ☹️☹️☹️☹️☹️☹️
Doss [256]
The answer would be C
7 0
2 years ago
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