D.10.0 mol is the correct
DeltaH formation = deltaH of broken bonds - deltaH of formed bonds
Broken bonds: tiple bond N-N and H-H bond
Formed bonds: N-H and N-N bonds
You also have to take note of the molar coefficients
deltaH formation = <span> [(N≡N) + 2 * (H-H)] - [4 * (N-H) + (N-N)]
= (945 + 2*436) - (4*390 + 240)
= 17 kJ/mol
The answer is 17 kJ/mol.</span>
Answer:
— The molality of chloride ions in 300g of water is. A) 1.00 molal. B) 0.500 molal. C) 0.0553 molal. D) 0.111 molal.
Answer:
Answers are bellow.
Explanation:
The element with electron configuration 1s22s22p63s1 belong I A group in the periodic table and it is sodium because it loses one electron.
We have periodic table in attachments.
Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table, because it has a single electron in its outer shell, which it readily donates, creating a positively charged ion—the Na+ cation. Its only stable isotope is 23Na.
The free metal does not occur in nature, and must be prepared from compounds.
It is soft metal, reactive and with a low melting point.