Y = |x| is a v-shaped graph that opens up and have vertex (0, 0).
Now we need to see each change done to it.
y = -|x| makes every y-coordinate its additive inverse, so y = -|x| still has the vertex at (0, 0), but now is turned downward.
y = -|x| + 2 can be changed to
y - 2 = -|x|
Now y was replaced by y - 2. When y is replaced by y - k, the graph shifts vertically k units. In this case, k = 2, so the graph shifts up 2 units. The vertex is now at (0, 2).
Vertex: (0, 2)
Domain: all real numbers
Range: all real numbers less than or equal to 2.
We are given: Function y=f(x).
First x-intercept of the y=f(x) is 2.
x-intercept is a point on x-axis, where y=0.
Replacing y by 0 and x by 2 in above function, we get
0=f(2)
Second x-intercept of the y=f(x) is 3.
Replacing y by 0 and x by 2 in above function, we get
0=f(3)
We are given another function y=8f(x).
Here only function f(x) is being multiplied with 8.
That is y values of function should be multiply by 8.
Because we have y value equals 0. On multiplying 8 by 0 gives 0 again and it would not effect the values of x's.
Therefore,
x-intercepts of y=8f(x) would remain same, that is 2 and 3.
1/45 that’s the right answer
First find slope
5-10/-1-0= 5
find y-intercept
10=5(0)+B
b=-10
equation: y=5x-10
Point c.
You can graph the two points in a calculator to find out the answer OR you can identify the lines using the y-intercept aka b in the y=mx+b format.
Y=x - 3 has a y-intercept of -3, so look for the line where it goes through -3 on the y axis. (do the same for the other except when the y-intercept is 1)
From this, you can identify the lines and just find where they intersect.