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sladkih [1.3K]
3 years ago
13

PLEASE HELP

Chemistry
2 answers:
vladimir2022 [97]3 years ago
6 0

james moore .............................

Ksenya-84 [330]3 years ago
5 0

Answer:

chcoooh and hco3 reactant

product the rest

arrow in the middle

write the full equation

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Plz!!!!!!!!!!!!!!!!!help!!!!!!!!!!!!!!!!!!!!
drek231 [11]
An electromagent is being shown. Because the picture is showing how to put the lightnulb in and where it is
8 0
3 years ago
A mineral is described as "metallic." This description refers to its:
abruzzese [7]

Answer: properties

Explanation:

The element which has the properties

Mallablity

Ductility

Lusterous

High electric. Conductivity

High tensile strength is said to be metal.

8 0
3 years ago
Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?
Step2247 [10]
Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

                               C     +     O2      ------>  CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2. 

                          <u>     86.5 g CO       </u>   = 1.966 moles CO2
                            44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel. 

        1.966 moles CO2   x   <u>   1 mole C   </u>    x   <u>   </u><u>12 g C   </u>  = 23.59 g C
                                             1 mole CO2          1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams. 


            25.0 g - 23.59 g = 1.41 grams Hydrogen 

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen. 

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel, 

Carbon:     <u>  1.966 mol   </u>   = 1.408   x   5 (factor)     = 7
                    1.396 mol

Hydrogen:  <u>  1.396 mol   </u>    = 1.00   x    5 (factor)    = 5
                     1.396 mol

Thus, the empirical formula is C7H5

       
4 0
4 years ago
Read 2 more answers
4. Substances that existed before mixing-still exist-after substances-are-mixed----
pantera1 [17]
False; Because when 2 substances are mixed another substance is created.
5 0
3 years ago
Which of the following is not an example of a physical property?
Viefleur [7K]
<span>c.
reactivity

this is a physical property depends on how reactive something is</span>
7 0
3 years ago
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