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iVinArrow [24]
3 years ago
8

Write the electron configuration, for an element with 30 electrons

Chemistry
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

Zinc (30)= [Ar]3d104s2 (electron configuration of Zinc)

Explanation:

Zinc:

Atomic Mass= 65.39 atomic mass units (amu)

Number of Protons= 30

Number of Neutrons= 35

Number of Electrons= 30

I hope this is what you were asking for!

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An acid and a base are mixed equally together in solution. what will likely happen?
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Mixing equal amounts of a strong acid with a strong base also produces a neutral pH (pH = 7) solution<span>.

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3 years ago
Read 2 more answers
1. What is the molarity of 6.4g of methanol dissolved in 50 moles of water2. If the density of the above solution at 25C is 1.03
ICE Princess25 [194]

Answer:

1. 0.22 mol/dm³

2. 0.23 mol/dm³

Explanation:

Molarity: This can be defined as the concentration of a substance  in mol per dm³

1.

M = n/v ...................... Equation 1

M = molarity of methanol, n = number of mole of methanol, v = volume of the solvent/water/solution.

<em>n = g/m.m</em>

<em>Where g = mass of methanol, m.m = molar mass of methanol.</em>

<em>g = 6.4 g, m.m = 32 g /mole.</em>

<em>n = 6.4/32 = 0.2 mole</em>

<em>and ,</em>

<em>v = m/d </em>

<em>Where m = mass of water, d = density of water</em>

<em>m = mass of 50 moles of water = 18×50 = 900 g.</em>

d = 1000 g/dm³.

v = 900/1000 = 0.9 dm³

Substituting the value of v and n into equation 1

M = 0.2/0.9

M = 0.22 mol/dm³

2.

M = n/v

v = volume of the solution

v = (mass of methanol + mass of water in the solution)/density of the solution

v = [(900+6.4)/1000]/1.03

v = 0.9064/1.03

v = 0.88 dm³

n = 0.2 mole

Therefore,

M = 0.2/0.88

M = 0.23 mol/dm³

3 0
3 years ago
Family members on a camping trip decide to make hot cocoa after dinner. They add instant cocoa mix to hot water. What can they d
zysi [14]

Answer:

Your ANSWER:

A.stir the hot cocoa

Explanation:

stirring helps particals dissolve faster

6 0
3 years ago
A compound D with the molecular formula C6H12 is optically inactive but can be resolved into enantiomers. On catalytic hydrogena
worty [1.4K]

Answer:

D: CH2=CH-CH(CH3)-CH2-CH3 (R & S enantiomers)

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(Please see the figures enclosed )

Explanation:

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E is optically inactive, so its structure has to be symmetric.

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4 years ago
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