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Scilla [17]
3 years ago
15

A rectangle has a perimeter of 30 inches.

Mathematics
1 answer:
erastova [34]3 years ago
8 0
The new perimeter would be 60. because the width and the height are doubled.
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I need help please! The sequence 6,18,54,162, ... shows the number of pushups Kendall did each week, starting with her first wee
Romashka-Z-Leto [24]

Answer:

a: 3

b. 6973568802

Step-by-step explanation:

a₁ = 6 , r = 3 , a₂₀ =?

Result:

a₂₀ = 6973568802

Explanation:

To find a₂₀ we use the formula

aₙ = a₁ · r ^ⁿ⁻¹

In this example we have a₁ = 6 , r = 3 , n = 20. After substituting these values to above

formula, we obtain:

aₙ = a₁ · r ^ⁿ⁻¹

a₂₀ = 6 · 3 ^²⁰⁻¹

a₂₀ = 6 · 1162261467

a₂₀ = 6973568802

3 0
3 years ago
2. If mZ1 = 71 degrees, find the measure of the other 7 angles.<br>​
Kobotan [32]
The measure of angles 1,4,5,8 are congruent meaning they’re the exact same. If angle 1 measures 71 degrees then that means that 4,5,8 also measure 71 degrees. Angles 1&2 are supplementary angles which means their sum is 180. Since we know that angle 1 measures 71 then we can find the measure of angle 2 by 71+x=180 and solve for x (angle 2) which is 109
Angles 2,3,6,7 are congruent which means they also equal 109
*** angles 1,4,5,8 = 71
Angles 2,3,6,7 = 109***
3 0
3 years ago
A woman is 6 years older than 3 times her daughters age. their ages total 46. what are their ages?
Darina [25.2K]

(46/3)-6=9

Her daughter is 9 years old and her mother is 37.

4 0
3 years ago
1. Carter bought 3 oxen, 4 cows and 6 calves for $260. He paid twice as much for a cow as for a calf
valentinak56 [21]

Answer:

120 for oxen, 80 for cows, 60 for calves

o = 2x

Step-by-step explanation:

3o + 4x + 6c = 260

x = 2c

o = 2x

6x + 4x + 3x = 260

13x = 260

260 / 13 = 20

3o = 6x = 120

4x = 80

6c = 3x = 60

o = 2x

4 0
2 years ago
(PARABOLA? BRAINLIEST + 20 POINTS) A building has an entry the shape of a parabolic arch 22 ft high and 28 ft wide at the base.
Keith_Richards [23]

Check the picture below.

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{let's use this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \begin{cases} h=0\\ k=0 \end{cases}\implies y=a(x-0)^2+0 \\\\\\ \textit{we also know that } \begin{cases} x=14\\ y=-22 \end{cases}\implies -22=a(14-0)^2+0 \\\\\\ -22=a(14)^2\implies -22=196a\implies \cfrac{-22}{196}=a\implies -\cfrac{11}{98}=a \\\\[-0.35em] ~\dotfill\\\\ y=a(x-0)^2+0\implies \boxed{y=-\cfrac{11}{98}x^2}

3 0
4 years ago
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