2) Using the following equation:

1. What specifically are you looking for in the IR spectrum to determine if the reaction has given the desired product? 2. What

Umnica [9.8K]

Answer:

You are looking for expected peaks in absorption spectra founded on structure of desired product, respectively on bound in desired compound. Every bond absorb specific energy from radiation which wavelength match to IR spectrum of light. Result of energy absorption is vibration of bond and bonded atoms (if they are not too heavy).That absorbed energy is seen as a peak in absorption spectra. These peaks are specific for each bound so you need to find peaks that mach to bounds in your desired compound and in that matter you can identify your compound.

In nuclear magnetic resonance you are looking for peaks specific for atoms in your desired compound (H or C atoms). When external magnetic field is applied, atom goes in higher energy state. When atoms goes "relaxing", it releasing energy that mach energy gap from relaxed end excited state. That energy is detected on nuclear magnetic resonance spectra and it depends on neighbor atom so you can determine the position of atoms and identify structure of desired compound.

For better results it is the best to combine these two methods.

Explanation:

7 0

3 years ago

What type of reaction is shown below c10H8+12O2 10co2+4H2O

MakcuM [25]

Answer:

Explanation:

Combustion. Have fun with that.

7 0

3 years ago

A sample of propane(c3h8)has 3.84x10^24 H atoms.

deff fn [24]

Answer:

A) 14. 25 × 10²³ Carbon atoms

B) 34.72 grams

Explanation:

1 molecule of Propane has 3 atoms of Carbon and 8 atoms of Hydrogen.

The sample has 3.84 × 10²⁴ H atoms.

If 8 atoms of Hydrogrn are present in 1 molecule of propane.

3.84 × 10²⁴ H atoms are present in

$\mathfrak{ \frac{3.8 }{8} \times 10 ^{24}}$

= 4.75 × 10²³ molecules of Propane.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

No. of Carbon atoms in 1 molecule of propane = 3

=> C atoms in 4.75× 10²³ molecules of Propane = 3 × 4.75 × 10²³

= 14.25 × 10²³ 

________________________________________

Gram Molecular Mass of Propane(C3H8)

= 3 × 12 + 8 × 1

= 36 + 8

= 44 g

1 mole of propane weighs 44g and has 6.02× 10²³ molecules of Propane.

=> 6.02 × 10²³ molecules of Propane weigh = 44 g

=> 4. 75 × 10²³ molecules of Propane weigh =

$\mathsf{ \frac{44 }{6.02 \times {10}^{23} } \times 4.75 \times {10}^{23} }$

$\mathsf{ = \frac{44 }{6.02 \times \cancel{{10}^{23} }} \times 4.75 \times \cancel{ {10}^{23}} }$

$\mathsf{ = \frac{44 }{6.02 } \times 4.75 }$

= 34.72 g

8 0

3 years ago

What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?

lawyer [7]

Density=2.35g/mL
Mass=33.67g

$\\ \star\sf\longmapsto Density=\dfrac{Mass}{Volume}$

$\\ \star\sf\longmapsto Volume=\dfrac{Mass}{Density}$

$\\ \star\sf\longmapsto Volume=\dfrac{33.67}{2.35}$

$\\ \star\sf\longmapsto Volume=14.32mL$

6 0

3 years ago

Why do you think steeples and roofs might appear green, but a copper square does not?

Masteriza [31]

Because the copper roofs, have been outside for a while and oxidization has occurred.
When metals become oxidized they rust, but when copper becomes oxidized, it turns greenish.
So copper roofs oxidize and turn green from being outside and a copper square doesn’t if it’s inside.

8 0

2 years ago