Answer:
16 g/L
Explanation:
Given that:-
Mass of sucrose added = 1.2 g
Volume of water = 75 mL = 0.075 L ( 1mL = 0.001 L )
%w/v is defined as the mass of the solution in 1 L of the solution.
So,
the titration of a 20.0 mL sample of an H2SO4 solution of unknown concentration requires 22.87mL of a 0.200M NaOH solution to re
1 answer:
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Answer:
<h3>The answer is 43.89 mL</h3>Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 57.5 g
density = 1.31 g/mL
We have
We have the final answer as
<h3>43.89 mL</h3>Hope this helps you