Ask question

Ask question

All categories

2 years ago

11

the titration of a 20.0 mL sample of an H2SO4 solution of unknown concentration requires 22.87mL of a 0.200M NaOH solution to re

ach the equivalence point. What is the concentration of the unknown acid solution?

1 answer:

nataly862011 [7]2 years ago

7 0

M =n/v
M= .23/.02
M=11.5

You might be interested in

the diagram below represents two beakers, each containing an ice cube and clear liquid. in beaker A the ice cube floats, and in

Mama L [17]

Answer:

The density of the liquid in beaker B is less than the that of ice.

Explanation:

Ice will float if its mass is less than the mass of the liquid it displaces.

For example, the density of ice is less than that of water.

A 10 cm³ cube of ice has a mass of about 9 g, while the mass of 10 cm³ of water is 10 g. Thus, 9 g of ice displaces 10 g of water.

The denser water displaces the lighter ice and the ice floats to the top.

If the density of the liquid is <em>less than</em> that of water, say, 8 g/cm³, the ice will displace only 8 g of the liquid. The ice will sink.

4 0

3 years ago

The firm outer covering of a plant cell is a

Verizon [17]

Answer:

it is the cell wall :)

Explanation:

5 0

2 years ago

Read 2 more answers

What is the molarity of 2.50 mol in a 1000 ml solution? *

VARVARA [1.3K]

Answer:

450na

Explanation:

from that solution

4 0

2 years ago

How many molecules are in 85g of silver nitrate?

maksim [4K]

<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Writing Compounds
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})$
Multiply/Divide: $\displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0

2 years ago

Write a balanced half-reaction for the reduction of permanganate ion mno−4 to solid manganese dioxide mno2 in acidic aqueous sol

Svetlanka [38]

The half-reaction includes either the reduction or the oxidation reaction of the redox reactions. In acidic solution permanganate ion will react with hydrogen ion to yield manganese ion and water.

<h3>What are Redox reactions?</h3>

Redox or oxidation-reduction reactions are the chemical reactions in which the oxidation and the reduction of the chemical species occur simultaneously.

Permanganate (VII) ion is a strong oxidizing agent and gets easily reduced to manganese ion in presence of the hydrogen ion in an acidic solution.

The balanced half-reaction for reduction is shown as,

$\rm MnO_{4}^{-} \; (aq)+ 8H^{+} \; (aq)+ 5e^{-} \rightarrow Mn^{2+} \; (aq)+ 4H_{2}O \; (l)$

Learn more about reduction reactions here:

brainly.com/question/10084275

#SPJ4

8 0

1 year ago