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Neporo4naja [7]
3 years ago
10

Which of the following information is necessary to describe an object's motion? position, speed, direction, position, direction,

and speed
Physics
1 answer:
erica [24]3 years ago
5 0
All of the above (position speed and direction)
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A 91 kg zebra is traveling 7 m/s east. What is the zebra’s momentum? kg-m/s
frez [133]
To find momentum you multiply the mass and velocity.
91 × 7 = 637 kg-m/s
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Name at least 4 things our atmosphere dose for us
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Gives us rain gives us air keeps us from dieing of cosmic radiation keeps us from literly cookin our selfs cause of the sun
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3 years ago
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The index of refraction for red light in a certain liquid is 1.303; the index of refraction for violet light in the same liquid
kotegsom [21]
Snell's law states: n1/n2 = Sin Ф2/Sin Ф1

But n2/n1 = 1.303 and 1.326 for red light and violet light respectively (for this case) and Ф1 = 45

Therefore,
Фr = Sin ^-1{1/1.303 *Sin 45} = 32.87°
Фv = Sin ^-1 {1/1.326* Sin 45} = 32.23°

Then,
Dispersion, Фv - Фr = 32.23 - 32.87 = -0.64°
3 0
4 years ago
If a brick falls from a building 23.0 meters tall, how much time does it take for it to hit the ground?​
Natalija [7]

Answer:

It will take t = 2.16 [s]

Explanation:

In order to solve this problem, we must find the final speed of the object when it is on the floor. The only way is to use the principle of energy conservation which tells us that potential energy can be transformed into kinetic energy and vice versa.

E_{p} = E_{k} \\m*g*h = \frac{1}{2} *m*v^{2}

Now we can find the velocity

v² = 2*g*h

v = √2*9.81*23

v = 21.24 [m/s]

Now using the following equation:

v_{f} = v_{o} +(g*t)\\

where:

Vf = final velocity = 21.24 [m/s]

Vo = initial velocity = 0

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

21.24 = 0 + (9.81*t)

t = 2.16 [s]

6 0
3 years ago
A point charge q1 is held stationary at the origin. A second charge q2 is placed at point a, and the electric potential energy o
Brrunno [24]

The electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

<h3>Electric potential energy</h3>

When work is done on a positive test charge to move it from one location to another, potential energy increases and electric potential increases.

The electric potential energy between the charges when the second charge is at point b is calculated as follows;

ΔU = -w

Ui - Uf = w

Uf = Ui - w

where;

Uf is the final potential energy

Ui is the initial potential energy

w is the work done by the force

Uf = 5.4 x 10⁻⁸ J - (-1.9 x 10⁻⁸J)

Uf = 5.4 x 10⁻⁸ J + 1.9 x 10⁻⁸ J

Uf = 7.3 x 10⁻⁸ J

Thus, the electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

Learn more about electric potential energy here: brainly.com/question/14306881

#SPJ1

7 0
2 years ago
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