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2 years ago

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Two small plastics balls are hanging on silk threads, 50 mm from each other. The charges on the balls are indicated 1.3.1 Calcul

ate the magnitude of the force that the balls iniatially exert on each other

1 answer:

Nastasia [14]2 years ago

5 0

I calculated the magnitude of the force that the balls imitially exert to each other

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When light propagates through two adjacent materials that have different optical properties, some interesting phenomena occur at

Veseljchak [2.6K]

Answer:

First, the different indices of refraction must be taken into account (in different media): for example, the refractive index of light in a vacuum is 1 (since vacuum = c). The value of the refractive index of the medium is a measure of its "optical density": Light spreads at maximum speed in a vacuum but slower in others transparent media; therefore in all of them n> 1. Examples of typical values of are those of air (1,0003), water (1.33), glass (1.46 - 1.66) or diamond (2.42).

The refractive index has a maximum value and a minimum value, which we can calculate the minimum value by means of the following explanation:

The limit or minimum angle, α lim, is defined as the angle of refraction from which the refracted ray disappears and all the light is reflected. As in the maximum value of angle of refraction, from which everything is reflected, is βmax = 90º, we can know the limit angle (the minimum angle that we would have to have to know the minimum index of refraction) by Snell's law:

βmax = 90º ⇒ n 1x sin α (lim) = n 2 ⇒ sin α lim = n 2 / n 1

Explanation:

When a light ray strikes the separation surface between two media different, the incident beam is divided into three: the most intense penetrates the second half forming the refracted ray, another is reflected on the surface and the third is breaks down into numerous weak beams emerging from the point of incidence in all directions, forming a set of stray light beams.

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3 years ago

What is the energy of an electromagnetic wave that has a frequency of 5.0 x 10⁵ Hz?

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3 years ago

A super snail initially traveling at 2 m/s accelerates at 1 m/s^2 for 5 seconds. How fast will it be going at the end of the 5 s

Vedmedyk [2.9K]

Answer:

The snail travel at the end of 5 s with a velocity of 12 m/s and the distance of the snail is 22.5 m.

Explanation:

Given that, the initial velocity of the snail is,

$u=2m/s$

And the acceleration of the snail is,

$a=1m/s^{2}$

And the time taken by the snail is,

$t=5 sec$

Now according to first equation of motion,

$v=u+at$

Here, u is the initial velocity, t is the time, v is the final velocity and a is the acceleration.

Now substitute all the variables

$v=2m/s+ 1 \times 5 sec\\v=7m/s$

Therefore, the snail travel at the end of 5 s with a velocity of 7 m/s.

Now according to third equation of motion.

$v^{2}- u^{2}=2as\\ s=\frac{v^{2}- u^{2}}{2a} \\$

Here, u is the initial velocity, a is the acceleration, s is the displacement, v is the final velocity.

Substitute all the variables in above equation.

$s=\dfrac{7^{2}- 2^{2}}{2(1)}\\s=\dfrac{45}{2}\\ s=22.5m$

Therefore the distance of the snail is 22.5 m.

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3 years ago