A space rocket accelerates uniformly from rest to 160ms^-1 upwards in 4.0s, then travels with a constant speed of 160ms^-1 for t
he next 5.0s.
What is the initial acceleration of the rocket?
What is the initial acceleration of the rocket?
1 answer:
Answer:
40 ms¯².
Explanation:
To solve this problem, we shall illustrate the question with a diagram.
The attached photo gives a better understanding of the question.
From the attached photo:
Velocity (v) = 160 ms¯¹
Time (t) = 4 secs.
Acceleration (a) =?
Acceleration (a) = Velocity (v) /time (t)
a = v/t
a = 160/4
a = 40 ms¯²
Therefore, the initial acceleration of the rocket is 40 ms¯².
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Answer:
Current, I = 5.3 A
Explanation:
It is given that,
Radius of circular loop, r = 3 mm = 0.003 m
Magnetic field strength, B = 1.1 mT = 0.0011 T
We need to find the magnitude of the current that flows through the wire. The magnetic field for a current carrying wire is given by :
I = 5.25 A
or
I = 5.3 A
So, the magnitude of the current that flows through the wire is 5.3 A. Hence, this is the required solution.