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1 year ago

A rock falls off a cliff. How fast will it be going after falling for 4.33 seconds?

Physics

1 answer:

bixtya [17]1 year ago

4 0

Answer:42.43m/s

Explanation:According to vf=vi+at, we can calculate it since v0 equals to 0. vf=0+9.8m/s^2*4.33s= 42.434m/s

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2. Which is longer? အ O 1 mile O 2 kilometers O 1000 mL O 850g

anastassius [24]

Answer:

•2 kilometres.................

5 0

3 years ago

A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 24 m/

PilotLPTM [1.2K]

Answer:

a) Vf = 27.13 m/s

b) It would have been the same

Explanation:

On the y-axis:

$Y=-Vo*sin\theta*t-1/2*g*t^2$

$-8=-24*sin(21)*t-1/2*10*t^2$

Solving for t:

t1 = 0.67s t2= -2.4s

Discarding the negative value and using the positive one to calculate the velocity:

$Vf_y = -Vo*sin\theta-g*t$

$Vf_y = -15.3m/s$

So, the module of the velocity will be:

$Vf=\sqrt{(-15.3)^2+(24*cos(21))^2}$

$Vf=27.13m/s$

If you throw it above horizontal, it would go up first, and when it reached the initial height, the velocity would be the same at the throwing instant. And starting then, the movement will be the same.

3 0

3 years ago

Isotopes of hydrogen react, forming the element helium, as shown.

forsale [732]

Answer:

B. nuclear fusion

Explanation:

Atomic fusion is a process in which two or more lighter nuclei combine to form a heavier nucleus.

The mass of the single nucleus thus formed is lighter than the initial mass.

There is a difference in mass in the heavier nucleus thus formed. According to Einstein's mass-energy equation, the change in mass is equated towards energy.

The energy liberated in the process is called as thermo-nuclear energy.

As in the case of isotopes of hydrogen fuses to form helium, the nuclear reaction is given by relation

₁H³ + ₁H² → ₂He⁴ + ₀n¹ + energy

Thus, the nuclear reaction of hydrogen isotopes forming helium is nuclear fusion.

6 0

3 years ago

Suppose a pendulum bob is swinging back and forth. If the highest point is 12.5 cm above the lowest point, what would be speed o

Colt1911 [192]

Answer:

The speed of the bob when it passes the lowest point $V = 1.57 \frac{m}{s}$