Answer:
![a=9\ cm/s^2](https://tex.z-dn.net/?f=a%3D9%5C%20cm%2Fs%5E2)
Explanation:
<u>Average Acceleration
</u>
Acceleration is a physical magnitude defined as the change of velocity over time. When we have experimental data, we can compute it by calculating the slope of the line in velocity vs time graph.
Note: <em>We cannot see if the time axis is numbered in increments of 1 second, and we'll assume that.
</em>
When
, the graph shows a value of
When
, the object is at rest, ![v_1=0](https://tex.z-dn.net/?f=v_1%3D0)
We compute the average acceleration as
![\displaystyle a=\frac{v_2-v_1}{t_2-t_1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7Bv_2-v_1%7D%7Bt_2-t_1%7D)
![\displaystyle a=\frac{36\ cm/s-0\ cm/s}{4\ sec-0\ sec}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7B36%5C%20cm%2Fs-0%5C%20cm%2Fs%7D%7B4%5C%20sec-0%5C%20sec%7D)
![\displaystyle a=\frac{36\ cm/s}{4\ s}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3D%5Cfrac%7B36%5C%20cm%2Fs%7D%7B4%5C%20s%7D)
![\boxed{a=9\ cm/s^2}](https://tex.z-dn.net/?f=%5Cboxed%7Ba%3D9%5C%20cm%2Fs%5E2%7D)
Distance between the two cars is increasing at the rate of 85 mph.
A passenger in Car-1 says that he is at rest in his own frame of reference,
and Car-2 is moving away from him at 85 mph, toward the west.
Answer:
A boat travels for three hours with a... A boat travels for three hours with a current of 3 mph and then returns the same distance against the current in four hours. What is the boat's speed in still water?
Explanation:
Answer:
1.4E-3J
Explanation:
Given that
Time = 8hrs = 28.8E3 seconds
Intensity= 90dB
D= 0.008m
Radius= 0.004m
So intensity is sound level Bis
10dBlog(I/Io)
I= 10 (B/10dB)Io
= 10( 90/10) x 10^-12
=0.001W/m²
But we know that
I = P/A
P= I πr²
= 5.02 x10^-8W
But energy is power x time
So E= 5.02E-8 x 28.8E3
= 1.4E-3J