Fnet=ma so m = fnet/a 100/5=20 the mass is 20
The value of Q will be -8 C.
In the presence of an electric or magnetic field, matter experiences a force due to its electric charge.
A moving electric charge generates a magnetic field, and an electric charge has an accompanying electric field.
The information provided in the issue is;
The separation between and is 2m.
The separation between and is 2m.
An origin charge equals +2 C
The electric fields are identical in magnitude but are facing in different directions. As a result, the following relationship can be used
Q/16=1/2
The value of Q will be -8 C.
Learn more about electric charge here
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#4174
Answer:
12m
Explanation:
To obtain the answer to the question given, we must observe the characteristics of image formed by a plane mirror.
The image formed by a plane mirror have the following characteristics:
1. Laterally inverted.
2. Same distance as the object from the mirror.
3. Same height as the object.
4. Virtual.
With the above information, we can calculate the distance between the boy and his image as follow:
Initially:
Object distance (u) = 4m
Image distance (v) = 4m
The boy moved 2m away, therefore:
Object distance (u) = 2 + 4 = 6m
Image distanc(v) = 2 + 4 = 6m
The distance between the boy and his image will be the sum of his distance (u) and image distance (v) i.e (u + v)
The distance between the boy and his image = 6 + 6 = 12m
Therefore, the distance between the boy and his image is 12m.
Answer:
Explanation:
a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²
b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m
c) CCW
d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²
e) CCW