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Virty [35]
4 years ago
11

An infrared spectrometer on Dawn found something unexpected on Ceres's surface. Its presence suggested that Ceres might have for

med farther from the Sun, or been impacted by objects from a more-distant part of the solar system. What was this finding
Physics
1 answer:
Sati [7]4 years ago
6 0

The question is missing alternatives. Here is the complete question.

An infrared spectrometer on Dawn found something unexpected on Ceres's surface. Its presence suggested that Ceres might have formed farther from the Sun, or been impacted by objects from a more-distant part of the solar system. What was this finding?

1. The fact that Ceres is covered with small dark particles  that appear identical to the composition of Uranus's rings.

2. The presence of a thick cloud layer made of sulfuric acid, similar to what is observed at Venus.

3. The presence of clay-like minerals with ammonia bound up in them.

4. The infrared spectrum of Ceres's surface is essentially identical to that of most objects in the Kuiper Belt.

Answer: 3. The presence of clay-like minerals with ammonia bound up in them.

Explanation: The discovery of ammonia clay-like minerals in Ceres is surprising because it would be encoutered in planets that are far from the Sun, since ammonia requires colder temperatures, which is found beyond Jupiter's orbit, to condense. This finding can ascertain not only the origins of the dwarf planet as how the solar system was formed, were organized and evolved, because understanding where smaller planets are formed is important to determine their destiny.

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Un carro de montaña rusa parte del reposo desde una primera cumbre, desciende una distancia vertical de 45 metros y luego sube u
garri49 [273]
A roller coaster car starts from the rest from a first summit, descends a vertical distance of 45 meters and then climbs a second summit, reaching the top with a speed of 15m / s. How high is the second summit? Do not consider friction


3 0
3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 500 rev/s. If such a star has a radius of 17
Alexus [3.1K]

Answer:

7.22 × 10²⁹ kg

Explanation:

For the material to be in place, the gravitational force on the material must equal the centripetal force on the material.

So, F = gravitational force = GMm/R² where M = mass of neutron star, m = mass of object and R = radius of neutron star = 17 km

The centripetal force F' = mRω² where R = radius of neutron star and ω  = angular speed of neutron star

So, since F = F'

GMm/R² = mRω²

GM = R³ω²

M = R³ω²/G

Since ω = 500 rev/s = 500 × 2π rad/s = 1000π rad/s = 3141.6 rad/s = 3.142 × 10³ rad/s and r = 17 km = 17 × 10³ m and G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

Substituting the values of the variables into M, we have

M = R³ω²/G

M = (17 × 10³ m)³(3.142 × 10³ rad/s)²/6.67 × 10⁻¹¹ Nm²/kg²

M = 4913 × 10⁹ m³ × 9.872 × 10⁶ rad²/s²/6.67 × 10⁻¹¹ Nm²/kg²

M = 48,501.942 × 10¹⁵ m³rad²/s² ÷ 6.67 × 10⁻¹¹ Nm²/kg²

M = 7217.66 × 10²⁶ kg

M = 7.21766 × 10²⁹ kg

M ≅ 7.22 × 10²⁹ kg

8 0
3 years ago
which has a greater kinetic energy, a bowling ball that has a mass of 5kg travelling at 6m/s, or a ship that has a mass of 12000
AVprozaik [17]

Answer:bowling ball has greater kinetic energy

Explanation:

Kinetic energy of bowling ball:

mass=m=5kg

Velocity=v=6m/s

Kinetic energy =ke

Ke=0.5 x m x v x v

Ke=0.5 x 5 x 6 x 6

Ke=90J

Kinetic energy of ship:

mass=m=120000kg

velocity=v=0.02m/s

Ke=0.5 x m x v x v

Ke=0.5 x 120000 x 0.02 x 0.02

Ke=24J

6 0
3 years ago
What place or system in which goods are traded illegally
monitta

The correct answer is the Black Market.

The Black Market refers to the informal (and sometimes formal) system of trading of illegal goods by merchants and dealers of products such a weapons, drugs, and good that have been banned by countries. This can also apply to informal marketplaces in countries with sanctions placed upon them get goods that formal treaties are blocking the people from accessing.

7 0
3 years ago
A soccer ball is kicked At 8m/s. It lands on the ground after being in the air for .85 seconds. At what angle is it kicked?
SpyIntel [72]

If ball remains in air for total time T = 0.85 s

this is also known as time of flight

In order to find the time of flight we can use kinematics

\Delta Y = v_y*t + \frac{1}{2}at^2

so for complete motion its displacement in y direction will be zero

0 = v_y* 0.85 + \frac{1}{2}(-9.8)(0.85^2)

0 = v_y*0.85 - 3.54

v_y = 4.165 m/s

now we know that net velocity of the ball is 8 m/s

while is y direction component we got is vy = 4.165 m/s

now by component method we can say

v_y = v sin\theta

4.165 = 8 sin\theta

\theta = sin^{-1}\frac{4.165}{8}

\theta = 31.4^0

so it is projected at an angle of 31.4 degree above horizontal

8 0
3 years ago
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