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Virty [35]
3 years ago
11

An infrared spectrometer on Dawn found something unexpected on Ceres's surface. Its presence suggested that Ceres might have for

med farther from the Sun, or been impacted by objects from a more-distant part of the solar system. What was this finding
Physics
1 answer:
Sati [7]3 years ago
6 0

The question is missing alternatives. Here is the complete question.

An infrared spectrometer on Dawn found something unexpected on Ceres's surface. Its presence suggested that Ceres might have formed farther from the Sun, or been impacted by objects from a more-distant part of the solar system. What was this finding?

1. The fact that Ceres is covered with small dark particles  that appear identical to the composition of Uranus's rings.

2. The presence of a thick cloud layer made of sulfuric acid, similar to what is observed at Venus.

3. The presence of clay-like minerals with ammonia bound up in them.

4. The infrared spectrum of Ceres's surface is essentially identical to that of most objects in the Kuiper Belt.

Answer: 3. The presence of clay-like minerals with ammonia bound up in them.

Explanation: The discovery of ammonia clay-like minerals in Ceres is surprising because it would be encoutered in planets that are far from the Sun, since ammonia requires colder temperatures, which is found beyond Jupiter's orbit, to condense. This finding can ascertain not only the origins of the dwarf planet as how the solar system was formed, were organized and evolved, because understanding where smaller planets are formed is important to determine their destiny.

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PLEASE HELP! 3 Questions, 10 points a question, will give brainliest.
Basile [38]

1) Mechanical energy is conserved in all the 4 situations

2) True

3) The potential energy of the block is 490 J

Explanation:

1)

Mechanical energy is the sum of potential energy (PE) and kinetic energy (KE) of a body:

E=PE+KE

According to the law of conservation of energy, in absence of non-conservative forces (such as air resistance, friction...), the mechanical energy of a body is always conserved.

This means that the mechanical energy is conserved in all the situations described. More specifically:

- Child on a swing : there is a continuous conversion between kinetic energy and gravitational potential energy

- Pendulum : there is a continuous conversion between kinetic energy and gravitational potential energy

Bow and Arrow : there is a conversion of energy from elastic potential (when the bow is stretched) to kinetic energy (when the arrow is shot)

Roller Coaster: there is a continuous conversion between kinetic energy and gravitational potential energy

2)

As we  said, the mechanical energy of the object falling down at any point of the fall is

E=KE+PE

where KE is the kinetic energy and PE is the potential energy. The value of E is constant, since the mechanical energy is conserved.

The potential energy is given by

PE=mgh

where m is the mass of the object, g is the acceleration of gravity, h is the height of the object above the ground.

As the object falls, its height h decreases, and therefore, the potential energy PE also decreases. But we said that E must remain constant: therefore, if PE decreases, this means that KE increases, therefore as the object falls, the potential energy is converted into kinetic energy (in fact, the  speed of the object increases). So the statement is true.

3)

The potential energy of an object is given by the equation

PE=mgh

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

h is the height of the object relative to the ground

For the block in this problem, we have:

m = 10 kg

h = 5 m

Substituting, we find its potential energy:

PE=(10)(9.8)(5)=490 J

Learn more about potential energy and kinetic energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

8 0
3 years ago
Elements of Music<br>Timbre<br>Dynamics<br>Rhythm<br>Form<br>Texture<br>Harmony<br>Style​
rodikova [14]

Explanation:

Rhythm, Harmony, Timbre, Dynamics, Texture, and Form

7 0
2 years ago
The temperature of a body falls from 30°C to 20°C in 5 minutes. The air
natulia [17]

Answer:

15.88°C I am not 100% sure this is right but I am 98% sure this IS right

7 0
2 years ago
If an object is propelled upward from a height of 128 feet at an initial velocity of 112 feet per​ second, then its height h aft
Marina CMI [18]

Explanation:

The equation of motion of an object is given by :

h(t)=-16t^2+112t+128

Where

t is the time in seconds

We need to find the time when the object hits the ground. When the object hits the ground, h(t) = 0

So,

-16t^2+112t+128=0

-t^2+7t+8=0

On solving above equation using online calculator, t = 8 seconds. So, the object hit the ground after 8 seconds. Hence, this is the required solution.

8 0
3 years ago
In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these s
riadik2000 [5.3K]

Answer:

Part a)

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

Explanation:

As we know that the see saw bar is massless so here torque due to two masses is given as

\tau = I\alpha

here we will have

\tau = (m_1g - m_2g)(\frac{L}{2})

now we will have inertia of two masses given as

I = (m_1 + m_2)(\frac{L}{2})^2

now we have

I = (m_1 + m_2)\frac{L^2}{4}

now the angular acceleration is given as

\alpha = \frac{\tau}{I}

so we have

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

Now if the rod is not massles then we will have total inertia given as

I = (m_1 + m_2)(\frac{L}{2})^2 + \frac{m_{bar}L^2}{12}

so we will have

I = (m_1 + m_2)\frac{L^2}{4} + \frac{m_{bar}L^2}{12}

now the acceleration is given as

\alpha = \frac{\tau}{I}

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

7 0
3 years ago
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