Answer:
The answer is the last one
Step-by-step explanation:
Hope this helps
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
we are given with an isosceles triangle with two congruent sides equal to 70 inches and an angle of 36 degrees in between the sides. We are asked for the area of the triangle. The formula is A = 0.5 * ab sin theta where a and b are the sides. The area is equal to 1440. 07 in2.
