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DanielleElmas [232]
2 years ago
15

What percentage of an iron anchor’s weight will be supported by buoyant force when submerged in salt water?

Physics
1 answer:
Ilia_Sergeevich [38]2 years ago
6 0

Answer:

0.87

Explanation:

To solve this, we use the principle of Archimedes. Archimedes Principal of flotation states that "the buoyant force of an object is equal to the total weight of the fluid it displaces."

In the attachment, I stated the mathemacal formula, of which

F(B) = The buoyant force

w(fl) = The weight of the salt water displaced

p(iron) = density of iron

p(salt) = density of the salt water = 1025 kg/m³

F' = weight of the iron in air

F = weight of the iron in salt water

p(man) = density of man = 7680 kg/m³

The rest are the easy calculations done by substituting the values

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A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m. If her pisto
lapo4ka [179]

Answer:

The diameter of the piston of the players equals 55.136 cm.

Explanation:

from the principle of transmission of pressure in a hydraulic lift  we have

\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}

Since the force in the question is the weight of the individuals thus upon putting the values in the above equation we get

\frac{57.0\times 9.81}{\frac{\pi \times (19.0)^{2}}{4}}=\frac{4\times 120\times 9.81}{\frac{\pi \times D_{2}^{2}}{4}}

Solving for D_{2} we get

D_{2}^{2}=\frac{4\times 120}{57}\times 19^{2}\\\\\therefore D_{2}=\sqrt{\frac{4\times 120}{57}}\times 19\\\\D_{2}=55.136cm

5 0
3 years ago
What day of the year is solar time the same as sidereal time?
Illusion [34]

Answer:

I think the answers March 21

6 0
2 years ago
Read 2 more answers
Q|C A string with linear density 0.500 g/m is held under tension 20.0 N. As a transverse sinusoidal wave propagates on the strin
julia-pushkina [17]

A string with linear density 0.500 g/m.

Tension 20.0 N.

The maximum speed  v_{y, max}

The energy contained in a section of string 3.00 m long as a function of v_{y, max}.

We are given following data for string with linear density held under tension :

μ = 0.5 \frac{g}{m}

  = 0.5 x 10⁻³ \frac{kg}{m}

T = 20 N

If string is L = 3m long, total energy as a function of v_{y, max} is given by:

E = 1/2 x μ x L x ω² x A²

  = 1/2 x μ x L x v^{2} _{y, max}

  = 7.5 x 10⁻⁴ v^{2} _{y, max}

So, The total energy as a function of  v^{2} _{y, max} = 7.5 x 10⁻⁴ v^{2} _{y, max}

Learn more about linear density problem here:

brainly.com/question/17190616

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3 0
2 years ago
The range of human hearing is roughly from twenty hertz to twenty kilohertz. Based on these limits and a value of 343 m/s for th
omeli [17]

Explanation:

It is given that, the range of human hearing is roughly from twenty hertz to twenty kilohertz.

Minimum frequency, f = 20 Hz

Maximum frequency, f' = 20,000 Hz

We need to find the lengths of the longest and shortest pipes. For open pipes, the length of pipe is given by :

l=\dfrac{v}{2f}

For shortest pipe, frequency should be maximum, l=\dfrac{343\ m/s}{2\times 20000\ Hz}

l = 0.008575 m

For longest pipe, frequency should be minimum, l'=\dfrac{343\ m/s}{2\times 20\ Hz}

l' = 8.575 m

So, the lengths of longest and shortest pipes are 8.575 meters and 0.008575 meters respectively.

4 0
3 years ago
A 20N net force acts upon an object with a mass of 4. 0kg. What is the object's acceleration?
galina1969 [7]

Answer:

5ms^-2

Explanation:

F = 20N, m = 4.0kg, a = ?

Using the formula for Force

F = ma

Then making acceleration the subject of the formula

a = F/m

a = 20N/4.0kg

a = 5ms^-2

8 0
2 years ago
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