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Anit [1.1K]
3 years ago
14

Is Mercury a heavier element than tin

Physics
1 answer:
Kryger [21]3 years ago
4 0
Yes because mercury has more protons and electrons that tin. (30 more)
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What is the force required to accelerate a baseball with a mass of 0.145 kilograms and an acceleration of 35.00 meters/second sq
Paladinen [302]

Answer:5.075N

Explanation:

Mass=0.145kg

Acceleration=35m/s^2

Force=mass x acceleration

Force=0.145 x 35

Force=5.075N

3 0
3 years ago
It is important to use the correct drying tempture because it prevents shrinkage and will not damage the garment.
Nina [5.8K]

Answer:

fjowe

Explanation:

kbegtrf3g4ef j3kq4ef 3w4beysrf2w4er8f6ywgbaebf7v2wy4egdwa4i6e5

7 0
3 years ago
Read 2 more answers
A 700 kg racecar slowed from 30 m/s to 15 m/s. What is the change in momentum
Lerok [7]

Momentum = (mass) x (speed)

Original momentum  =  (700 kg) x (30 m/s)  =  21,000 kg-m/s

Final momentum = (700 kg) x (15 m/s)  =  10,500 kg-m/s

Change in momentum  =  - 10,500 kg-m/s .
8 0
3 years ago
A parallel plate capacitor filled with air with plate area 2-cm2 and plate separation of 0.5 mm is connected to a 12 V batter an
pashok25 [27]

Answer:

a) The charge of the capacitor is 4.25x10⁻¹¹C

b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.

c) The potential difference across the plates is 18 V

d) The work is 7.64x10⁻¹⁰J

Explanation:

The capacitance of the capacitor is equal to:

C=\frac{e_{0}A }{d}

A = 2 cm² = 0.0002 m²

d = 0.5 mm = 0.0005 m

Replacing:

C=\frac{8.85x10^{-12}*0.0002 }{0.0005} =3.54x10^{-12} F = 3.54pF

a) The charge of the capacitor is equal to:

Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C

b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)

c) If distance is increased, we have:

C=\frac{8.85x10^{-12}*0.0002 }{0.00075} =2.36x10^{-12} F=2.36pF

The potential is:

V=\frac{Q}{C} =\frac{42.48}{2.36} =18V

d) The work done is equal to:

W=VQ=18*42.48=764.6pJ=7.64x10^{-10} J

3 0
3 years ago
Read 2 more answers
The y-position of a damped oscillator as a function of time is shown in the figure.
MrRissso [65]

The length of time that an oscillator is allowed to oscillate, as well as its damping coefficient.

  • t= 1.33s
  • b = 0.0426 s^-1

<h3>What is the period of the oscillator, and what factors influence the amount of damping that it has?</h3>

In most situations, the equation may be expressed numerically as

When we look at the data and see that there are cycles between the timestamps t= 0s and t= 4s, we may conclude that it finishes three cycles once every four seconds. As a result, the length of time that is going to be necessary to finish one cycle of damping will be

t =4/3sec

t= 1.33s

In most situations, the equation for amplitude may be expressed analytically as

A=A_0e^{-bt}

Therefore

3=5e^{-12b}

0.6=e^{-12b}

Therefore

-0.511 = -12b lne

b = 0.0426 s^{-1}

In conclusion, damping refers to an influence that either operates from inside an oscillatory system or acts on it and has the consequence of reducing or halting the system from oscillating. This impact might occur from either side of the system. In physical systems, damping is produced by processes that cause the energy that is stored in an oscillation to be lost. These processes are called dissipative. The collective name for these processes is "damping agents." The damping coefficient may thus be written as

b = 0.0426 s^-1

Learn more about the damping coefficient by reading up on it.

brainly.com/question/15723320

#SPJ1

4 0
1 year ago
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