In a lab, a student drags a shoe across the floor at constant speed. If the coefficient of static friction between the floor and
2 answers:
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Answer:
The ball travels <u>1.31 m horizontally</u> before hitting the ground.
Explanation:
Given:
Initial velocity of the ball is,
Angle of projection is,
Initial height of the ball is,
Final height of the ball is,
Now, horizontal and vertical components of initial velocity are given as:
Plug in the given values and find . This gives,
Now, there is acceleration due to gravity acting in the vertical direction. The direction is downward. So, .
Now, using equation of motion in the vertical direction, we have:
Plug in the given values and solve for time 't'. This gives,
On solving the above quadratic equation, we get:
Ignoring the negative result as time can't be negative. So, time taken by the ball to reach the ground is 0.57 s.
Now, as the ball moves, there is no force acting on it in the horizontal direction. So, the acceleration in the horizontal direction is 0.
Now, we know that, when acceleration is zero, the body moves with a constant speed.
Hence, distance traveled in the horizontal direction is given as:
Horizontal distance = Horizontal component of initial velocity × Time
Plug in the given values and solve for 'R'. This gives,
So, the ball travels 1.31 m horizontally before hitting the ground.
Answer:
patient receiving drug 25 MCG/minute
Explanation:
given data
infusing = 15 ml/hr
drug = 50 mg
D5W = 500 ml
to find out
How many MCG/minute
solution
we know infusing rate is 15 ml/hr = 0.25 ml/min
so 0.25 ml drug content = 50 /500 × 0.25
0.25 ml drug content = 0.025 mg
so here
rate of drug will be 0.025 mg
rate of drug = 0.025 mg = 25 × gm/min
rate of drug = 25 MCG/minute
so patient receiving drug 25 MCG/minute