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Mama L [17]
2 years ago
15

Assume that f(3) = 4. Name a point that must be on the graph of y=f(x)+4.

Mathematics
1 answer:
katrin [286]2 years ago
7 0

Answer:

(3,8)

Step-by-step explanation:

f(3)= 4 so y=f(3) +4 y =8 when x =3

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Theo bought two hot dogs and two sodas for $4.00. At the same concession stand, Vicky bought three hot dogs and a soda for $4.50
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Read 2 more answers
Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),
amm1812

Answer:

Step-by-step explanation:

Approximate the integral \int\int\limits_R {f(x,y)} \, dA by dividing the region R with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i

Since all are equal squares, so \delta A_i=1 for every i

\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24

Thus, \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24

Evaluating the iterate integral \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.

Thus, \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=24

7 0
3 years ago
Which one is it a b or c or d . ?
Svetach [21]
I think the answer is b
3 0
3 years ago
I need help with the two ones in the middle please | 15 pts.
Aloiza [94]

First answer: 6 and 8

6 + 8 = 14

6 * 8 = 48

Second answer: 14 in the middle, 350 on top.

39 - 25 = 14

25 * 14 = 350

8 0
3 years ago
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