Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.
Answer:
2.8
Step-by-step explanation:
The weighted average is found by dividing the total number of points by the total number of credits.
GPA = (4×3 + 3×4 + 3×4 + 3×4 + 2×3 + 1×2) / (3 + 4 + 4 + 4 + 3 + 2)
GPA = 56 / 20
GPA = 2.8
Answer:
90 (angle in a semicircle)
Answer:
27
Step-by-step explanation:
7x3=21
if that's 3 that's means 9x3 is the answer and its 27
keep dividing by the prime numbers is ascending order 2, 3 5 ....... ( if they are factors) , of course) until you end up with a prime number:-
80 / 2 = 40
40 / 2 = 20
20 / 2 = 10
10 / 2 = 5
So 80 = 2*2*2*2*5