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2 years ago

A) Which of the following equations model the law of conservations of mass? Ca + 2HCI - H2 + CaCl2 or

Chemistry

1 answer:

nydimaria [60]2 years ago

4 0

Answer:

The first equation

Explanation:

For these problems, it is best to label and record how many of each element are on each side of the equation. The first equation has 1 Ca, 2H, and 2Cl on both sides while the second equation has 3H on the left and 2H on the right making the second equation incorrect.

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If I contain 3 moles of gas in a container with a volume of 60 liters and at a

viktelen [127]

Answer: n = 3.0 moles

V = 60.0 L

T = 400 K

From PV = nRT, you can find P

P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L

P = 1.642 atm = 1.6 atm (to 2 significant figures)

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3 years ago

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Easyyy plz<br><br><br><br><br><br><br>What Is the Reactivity Series? ...

uysha [10]

Answer:

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3 years ago

A fixed mass of gass occupies a volume of 200cm at 21°c calculate it's volume at standard temperature

elena55 [62]

The answer is in the attachment below:

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2 years ago

calculate the mass required to prepare 2.5 L of 1.0 M NaOH solution. Given that the molar mass for NaOH is 40 g/mol.

Helen [10]

Answer:

The required mass to prepare 2.5 L of 1.0 M NaOH solution is 100 g

Explanation:

We do this by preparing the equation:

Mass = concentration (mol/L) x volume (L) x Molar mass

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3 years ago

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A vessel of volume 100ml contains 10% of oxygen and 90% of an unknown gas. The gases diffuses in 86 second through a small hole

swat32

The molecular weight of unknown gas : 23.46 g/mol

<h3>Further explanation</h3>

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

$\tt 0.1\times 32+0.9\times M=3.2+0.9M$

Graham's Law :

$\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol$

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3 years ago