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4 years ago

Please someone answer urgent will give thanks and mark brainliest

Mathematics

1 answer:

ANTONII [103]4 years ago

4 0

Which rug is which? I need to know before I can give the correct answer

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The main tank has a radius of 70 feet. What is the volume of the quarter-sphered sized tank? Round your answer to the nearest wh

Misha Larkins [42]

Volume of a sphere with radius of 70 feet is:
$V = \frac{4}{3} * \pi * r^{3}$

where r is that radius

Because we need quarter sized tank of that radius we need to divide formula for volume by 4

Than we get:
$V = \frac{1}{3} * \pi * r^{3}$

V = 359188,76

Rounded:
V = 359189

8 0

3 years ago

Consider the following 8 numbers, where one labelled x is unknown. 4, 32, 6, x , 10, 3, 35, 37 Given that the range of the numbe

Natali [406]

Answer:

$\boxed{x=-27, \: x=67}$

Step-by-step explanation:

There can be two values of x.

The range is largest no. - smallest no.

Range = 64

Let x be the smallest no.

largest no. from the list is 37

37 - x = 64

-x = 64 - 37

x = -27

Let x be the largest no.

smallest no. from the list is 3

x - 3 = 64

x = 64 + 3

x = 67

8 0

3 years ago

Read 2 more answers

A pyramid of volume 344 square units is sliced into two pieces by a plane parallel to the base of the pyramid and 10 units away

Tom [10]

Answer:

80 units

Step-by-step explanation:

v = 1/3 bh

v₁ = 1/3 * b * h₁ = 344

v₂ = 1/3 * b * h₂ = 301

v₁ / v₂ = h₁ / h₂ = 344 / 301

h₂ = h₁ - 10

h₁ / (h₁ - 10) = 344 / 301

344 * (h₁ - 10) = 301 * h₁

344* h₁ - 3440 = 301 * h₁

43 * h₁ = 3440

h₁ = 80

4 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$