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Kitty [74]
2 years ago
14

What is the electrical power when the current is 20 amps and the voltage is 15 volts? *

Physics
1 answer:
Nana76 [90]2 years ago
5 0

Answer:

The power is 300 watts.

Explanation:

Given that,

Current, I = 20 a

Voltage, V = 15 volts

The electrical power of any device is given by the product of current and voltage. It can be given by :

P = VI

So,

P = 15 × 20

= 300 W

So, the power is 300 watts.

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ryzh [129]

Answer:

A turbine and generator produce the electricity

Explanation:

"A hydraulic turbine converts the energy of flowing water into mechanical energy. A hydroelectric generator converts this mechanical energy into electricity.

8 0
2 years ago
A 4 kg bowling ball rolls at a speed of 5 m/s on the roof of a building that is 30 meters tall. What is its kinetic energy?
klasskru [66]

ans: B

Kinetic energy = \frac{1}{2} mv^{2}

= \frac{1}{2} (4)(5^{2} )

= 50J

ps. the height will only affect its potential energy, not kinetic.

3 0
3 years ago
If the mass of an object were doubled, its acceleration due to gravity would be
svetoff [14.1K]
Unchanged because ALL objects fall at 9.8m/s^2. Yes, all
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3 years ago
Read 2 more answers
Calculate the broadcast wavelength of the radio station 99.90 fm. seconds
taurus [48]

The radio waves are electromagnetic wave, so it travels with velocity of light i.e 3\times 10^{8} \ m/s.

We can use the relation between frequency, wavelength and speed as

\lambda =\frac{c}{f}

Here c is speed of light, \lambda is wavelength and f is frequency and its value is given 99.90 FM, it is actually in megahertz  (i.e 99.90 MHz).

Therefore,

\lambda =\frac{3 \times 10^{8}\ m/s }{99.90 \times 10^{6} \ Hz} = 3.003 \ m.

Thus, the broadcast wavelength of the given radio station is 3.003 m.

8 0
3 years ago
A scientist directs monochromatic light toward a single slit in an opaque barrier. The light has a wavelength of 580 nm and the
vredina [299]

Answer:

a) 9.72 mm

b) 4.86 mm

Explanation:

wave length of light  λ is  580 nm = 580 \times 10⁻⁹ m

Width of slit d = 0.215\times 10⁻³ m

Distance of screen D  = 1.8 m.

Width of one fringe = \frac{\lambda\times D}{d}

Putting the values we get fringe width

= \frac{580\times10^{-9}\times1.8}{.000315}

=4.86 mm.

a) Width of central maxima = 2 times width of one fringe

= 2 times 4.86

=9.72 mm

b) width of each fringe except central fringe  is same , no matter what the order is.Only brightness changes .

So width of either of the two first order bright fringe will be same and it will be  

= 4.86 mm.

3 0
2 years ago
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