<h2>If the distance between Earth and moon is increased , the gravitational force will decrease by a proportional amount .</h2><h2>The iron filings sprinkle around the magnet are arranged in regular pattern . The reason for this is that magnet can attract magnetic substances through various materials .</h2>
Explanation:
If the distance between Earth and moon is increased , the gravitational force will decrease by a proportional amount .
The iron filings sprinkle around the magnet are arranged in regular pattern . The reason for this is that magnet can attract magnetic substances through various materials .
In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.
<u>Explanation:</u>
An object experiences impulse due to the force exerted upon it in a particular time period.
i.e.

Where,
F - Force acted upon the object
- time interval for which the force act
According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).
Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.
Answer:
9.412 rad/s.
Explanation:
Velocity is the rate of change of an object's position.
V = x/t
Where x is the distance in m
= 2.4 m
t is time taken in s
= 8.5 s
V = 2.4/8.5
= 0.2824 m/s.
Equating linear velocity and angular velocity,
V = ω*r
Where,
ω Is the angular speed in rad/s
r is the radius of the circle in m
= 3 cm
= 3cm * 1m/100 cm = 0.03 m
ω = V/r
= 0.2824/0.03
= 9.412 rad/s.
The potential energy of the car when it let go is 20,000 J.
The speed of the car at the bottom of the ramp is 20 m/s.
The given parameters;
- <em>mass of the car, m = 100 kg</em>
- <em>height of the car, h = 20 m</em>
<em />
The potential energy of the car is calculated as follows;
P.E = mgh
P.E = 100 x 10 x 20
P.E = 20,000 J
The speed of the car at the bottom of the ramp is calculated as follows;

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