Solution :
a). From Newtons second law,
F = ma
The total tension force is 2T.
∴ 2T - (m + M)g = (m+ M)a
Then



b). From the person,
F = ma
T - Mg + N = Ma
or N = Ma + Mg - T
= (63 x 9.8) + (52 x 9.8) - 600
= 617.4 + 509.6 - 600
= 527 N
Answer:

Explanation:
The equation of the position in kinematics is given:

- x(0) is the initial position, in this it is 0
- v(0) is the initial velocity (20 m/s)
- a is the acceleration (2 m/s²)
So the equation will be:

Now, the Taylor polynomial equation is:

Using our position equation we can find f'(t)=v(t) and f''(x)=a(t). In our case a=0, so let's find each derivative.



Using the Taylor polynomial with a = 0 and take just the second order of the derivative.







Let's put t=1 so find the how far the car moves in the next second:


Therefore, the position in the next second is 21 m.
We need to know if the acceleration remains at this value to use this polynomial in the next minute, so I suggest that it would be reasonable to use this method just under this condition.
I hope it helps you!
Answer:
27.5 m/s
Explanation:
applying motion equations we can find the answer,
v = u + a*t
Let assume ,
u = starting speed(velocity)
v = Final speed (velocity)
t = time taken for the motion
a = acceleration
by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero (only a vertical speed component is there)
for the complete motion it takes 5.5 s. that means to reach the highest point it will take 5.5/2 =2.75 seconds
we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g=10 m/s2)
that is,
v = 0 , a = -10
, t =2.75
v = u + at
0 = u -10*2.75
u = 27.5 
Answer:
Transverse wave
Explanation:
The wave is moving forwards from the hand to the point of attachment