To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.
Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds
Horizontal distance
=0.335s*1.2m/s
=0.402 meters
Answer:
- No, this doesn't mean the electric potential equals zero.
Explanation:
In electrostatics, the electric field
is related to the gradient of the electric potential V with :

This means that for constant electric potential the electric field must be zero:





This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

give an electric field of zero at point (0,0,0)
Answer:
Easy search it on g o o g l e
Answer:
The minimum coefficient of friction is 0.544
Solution:
As per the question:
Radius of the curve, R = 48 m
Speed of the car, v = 16 m/s
To calculate the minimum coefficient of static friction:
The centrifugal force on the box is in the outward direction and is given by:

where
= coefficient of static friction
The net force on the box is zero, since, the box is stationary and is given by:
Answer:
the similarity is that hands are applied and force