The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge
Given values:
V = 6V, q = 1.6x10^-19C
Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ
Answer:
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The answer for this question is neon
The car is staying still. either getting petrol or stopped at a light .
Answer:
The correct answer should be
A. 20 Joules
Explanation:
I'm taking the K12 Unit Test: Energy - Part 1 right now
