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Sergeeva-Olga [200]
2 years ago
9

HELP ME PLEASE PLEASE PLEASE IM TAKING A TIMED TEST

Chemistry
2 answers:
cricket20 [7]2 years ago
4 0

Answer: oxygen

Explanation: trust me bro

iragen [17]2 years ago
3 0

Answer: I think it is silver

Explanation:

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What is the density of ice at -10°C?
Alisiya [41]

Answer:

3.98 C my friend you welcome

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3 years ago
The Loch Ness monster is a sea serpent that is thought to live in a lake in
Dmitry_Shevchenko [17]

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Scotland

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5 0
3 years ago
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Suppose 550.mmol of electrons must be transported from one side of an electrochemical cell to another in 49.0 minutes. Calculate
nekit [7.7K]

Answer:

18.0 Ampere is the size of electric current that must flow.

Explanation:

Moles of electron , n = 550 mmol = 0.550 mol

1 mmol = 0.001 mol

Number of electrons = N

N=N_A\times n

Charge on N electrons : Q

Q = N\times 1.602\times 10^{-19} C

Duration of time charge allowed to pass = T = 49.0 min = 49.0 × 60 seconds

1 min = 60 seconds

Size of current : I

I=\frac{Q}{T}=\frac{N\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}

=\frac{n\times N_A\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}

I=\frac{0.550 mol\times 6.022\times 10^{23} mol^{-1}\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}=18.047 A\approx 18.0 A

18.0 Ampere is the size of electric current that must flow.

3 0
3 years ago
A tank of gas has partial pressures of nitrogen and oxygen equal to 1.61 × 104 kPa and 4.34 × 103 kPa , respectively.What is t
Alchen [17]

Answer:

20.44\times 10^3 kPa is the total pressure of the tank.

Explanation:

Partial pressures of nitrogen = p_{N_2}=1.61\times 10^4 kPa

Partial pressure of oxygen =  p_{O_2}=4.34\times 10^3 kPa

Total pressure of gases in the tank = P

Applying Dalton's law of partial pressures :

P=p_{N_2}+p_{O_2}=1.61\times 10^4 kPa+4.34\times 10^3 kPa

P=20.44\times 10^3 kPa

20.44\times 10^3 kPa is the total pressure of the tank.

7 0
2 years ago
Calcium oxide and oxygen gas are produced by the thermal decomposition of limestone in the reaction CaCO (s) CaO(s) + CO (g). Wh
kozerog [31]
The mass of lime that  can  be produced  from  4.510 Kg of limestone  is calculated  as  below

calculate the moles  of CaCO3  used

that is  moles =mass/molar mass
convert  Kg  to g  = 4.510 x1000 =4510g
=  4510 / 100 =45.10 moles
CaCO3 = CaO  +O2

by use of mole ratio between CaCO3  to CaO  (1:1) the  moles of CaO  is also= 45.10 moles
mass of CaO = moles x molar  mass

45.10  x56 = 2525.6  g  of  CaO



6 0
3 years ago
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